100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
General Chemistry The Essential Concepts 7th Edition By Raymond Chang, Kenneth Goldsby (Solution Manual) $13.49   Add to cart

Exam (elaborations)

General Chemistry The Essential Concepts 7th Edition By Raymond Chang, Kenneth Goldsby (Solution Manual)

 28 views  0 purchase
  • Course
  • General Chemistry The Essential Concepts, 7e Raymo
  • Institution
  • General Chemistry The Essential Concepts, 7e Raymo

General Chemistry The Essential Concepts, 7e Raymond Chang, Kenneth Goldsby (Solution Manual) General Chemistry The Essential Concepts, 7e Raymond Chang, Kenneth Goldsby (Solution Manual)

Preview 4 out of 203  pages

  • June 20, 2023
  • 203
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers
  • General Chemistry The Essential Concepts, 7e Raymo
  • General Chemistry The Essential Concepts, 7e Raymo
avatar-seller
tutorsection
(General Chemistry The Essential Concepts, 7e Raymond Chang, Kenneth Goldsby)
(Solution Manual, For Complete File, Download link at the end of this File)


CHAPTER 1
INTRODUCTION
1.1 (a) Matter is anything that occupies space and has mass. (b) Mass is a measure of the quantity of matter in an
object. (c) Weight is the force that gravity exerts on an object. (d) A substance is matter that has a definite or
constant composition and distinct properties. (e) A mixture is a combination of two or more substances in
which the substances retain their distinct identities.

1.2 The scientifically correct statement is, “The mass of the student is 56 kg.”

1.3 Table salt dissolved in water is an example of a homogeneous mixture. Oil mixed with water is an example of
a heterogeneous mixture.

1.4 A physical property is any property of a substance that can be observed without transforming the substance
into some other substance. A chemical property is any property of a substance that cannot be studied without
converting the substance into some other substance.

1.5 Density is an example of an intensive property. Mass is an example of an extensive property.

1.6 (a) An element is a substance that cannot be separated into simple substances by chemical means.
(b) A compound is a substance composed of atoms of two or more elements chemically united in fixed
proportions.

1.7 (a) Chemical property. Oxygen gas is consumed in a combustion reaction; its composition and identity are
changed.
(b) Chemical property. The fertilizer is consumed by the growing plants; it is turned into vegetable matter
(different composition).
(c) Physical property. The measurement of the boiling point of water does not change its identity or
composition.
(d) Physical property. The measurement of the densities of lead and aluminum does not change their
composition.
(e) Chemical property. When uranium undergoes nuclear decay, the products are chemically different
substances.

1.8 (a) Physical change. Helium is not changed in any way by leaking out of the balloon.
(b) Chemical change in the battery.
(c) Physical change. The orange juice concentrate can be regenerated by evaporation of the water.
(d) Chemical change. Photosynthesis changes water, carbon dioxide, and so on, into complex organic
matter.
(e) Physical change. The salt can be recovered unchanged by evaporation.

1.9 (a) extensive (b) extensive (c) intensive (d) extensive

1.10 (a) extensive (b) intensive (c) intensive

1
© 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any
manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.

,2 CHAPTER 1: INTRODUCTION




1.11 (a) element (b) compound (c) element (d) compound




2
© 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any
manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.

, CHAPTER 1: INTRODUCTION 3




1.12 (a) compound (b) element (c) compound (d) element

1.13 (a) m (b) m2 (c) m3 (d) kg (e) s (f) N (g) J (h) K


1.14 (a) 106 (b) 103 (c) 10−1 (d) 10−2 (e) 10−3 (f) 10−6 (g) 10−9
(h) 10−12

1.15 Density is the mass of an object divided by its volume. Chemists commonly use g/cm3 or equivalently g/mL
for density. Density is an intensive property.

5C
1.16 ? C = (F − 32F) 
9F
 9F 
? F =  C  + 32F
 5C 


1.17 The density of the sphere is given by:

m 1.20  104 g
d = = = 11.4 g/cm3
V 1.05  103 cm3

1.18 Strategy: We are given the density and volume of a liquid and asked to calculate the mass of the liquid.
Rearrange the density equation, Equation (1.1) of the text, to solve for mass.
mass
density =
volume

Solution:
mass= density  volume

13.6 g
mass of Hg =  95.8 mL = 1.30  103 g
1 mL


5C
1.19 (a) ? C = (105 − 32)F  = 41C
9F
 9F 
(b) ? F =  −11.5 C  + 32F = 11.3 F
 5C 
 9F 
(c) ? F =  6.3  103 C  + 32F = 1.1  104 F
 5C 
5C
(d) ? C = (451 − 32)F  = 233C
9F

1.20 Strategy: Find the appropriate equations for converting between Fahrenheit and Celsius and between
Celsius and Fahrenheit given in Section 1.5 of the text. Substitute the temperature values given in the
problem into the appropriate equation.


3
© 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any
manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.

, 4 CHAPTER 1: INTRODUCTION



Solution:
1K
(a) K = (C + 273C)
1C
(i) K= 113C + 273C =386 K
(ii) K= 37C + 273C =3.10  102 K
(iii) K= 357C +273C=6.30  102 K

1K
(b) K = (C + 273C)
1C
(i) C= K − 273 = 77 K − 273 =−196C
(ii) C= 4.2 K − 273 =−269C
(iii) C= 601 K − 273 =328C


1.21 (a) 2.7  10−8 (b) 3.56  102 (c) 9.6  10−2

1.22 Strategy: Writing scientific notation as N 10n, we determine n by counting the number of places that the
decimal point must be moved to give N, a number between 1 and 10.
If the decimal point is moved to the left, n is a positive integer, the number you are working with is larger
than 10. If the decimal point is moved to the right, n is a negative integer. The number you are working with
is smaller than 1.

(a) Express 0.749 in scientific notation.

Solution: The decimal point must be moved one place to give N, a number between 1 and 10. In this case,
N = 7.49

Since 0.749 is a number less than one, n is a negative integer. In this case, n = −1.

Combining the above two steps:
0.749 = 7.49  10−1

(b) Express 802.6 in scientific notation.

Solution: The decimal point must be moved two places to give N, a number between 1 and 10. In this case,
N = 8.026

Since 802.6 is a number greater than one, n is a positive integer. In this case, n = 2.

Combining the above two steps:
802.6 = 8.026  102

(c) Express 0.000000621 in scientific notation.

Solution: The decimal point must be moved seven places to give N, a number between 1 and 10. In this
case,
N = 6.21

Since 0.000000621 is a number less than one, n is a negative integer. In this case, n = −7.
4
© 2014 by McGraw-Hill Education. This is proprietary material solely for authorized instructor use. Not authorized for sale or distribution in any
manner. This document may not be copied, scanned, duplicated, forwarded, distributed, or posted on a website, in whole or part.

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller tutorsection. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $13.49. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

67163 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$13.49
  • (0)
  Add to cart