Summary
Summary 1st term PFC CHEM1111
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A condensed summary of all relevant equations and graphs for physics for chemists term 1, with detailed explanations. This significantly reduces time spent revising this module.
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Vector Algebra·
(a1 is magnitude of a, if this is 1 then it's a
mit vector, represented by a
· Vector
of zolength is the null vecto -8) (bold zero
Normalisation
to find unit vector do A
1a1
Centre of mass equation
[2 =2 -
0
Itotal
what is the angle betwee
mass of e.g 1)b (5,
(2,2, 3,4)
-
molente
a
= =
hydrogen
-
(a) (2 3 12
:if diatomic
+ =
=
(b) (5312 558
= +
=
there
moleute
of are a.b (2)(5) (2)( 3) 1 17(R)
-
+ -
the divide
+
=
e.8
= 2
byz, if coso =
cosO=
s
Eso
840
0
=
scalar dot product ↑
dot product is and a gives
mal
a.b
a magnitudes as a direction of velocity3) and
=
bond angle
gives
between two sides.
(abi)i [dyby(j (acbz(k
9.b =
+
Divide by unit vector length, e.g
overall
+
if gives value of -1,
meay bonds are 1800 to
each other
cross product
cross product by two lines
|axbl absinO and b
=
gives line at
~
magnitudes of a a
have
normaldisease
(9ybz xzby)i (a2bx anbz)j
In
axb
(anby -aybx)l
=
-
+ -
+
A
=
a
dee use matrices to calculate
this formula
and then rearrange.
more
easing
so form
Mis
I laybaitasbitcan
sell-bearin-Byai-base in
Find
determinant
lit:it is it) b Gross produt
↳ to two original
othogonal
=
-
43i +
135 k
+
vectors
, ↑inematics
v
A=
=
a
d=
=
for object with constant acceleration
r(t)
Jadt
=
-at + ro-constant/velocity at t 0)=
r(t) =
SrC+)d+
=
((at voldf +
taterot
=
+ro-where - is is
the initial
position
Newton's first Law
A body remains at rest or trounds at a constant velocity unless
a net external force acts on it,
Newtons second Law
of body to the net force
the acceleration a is proportional
acting on it and inversely proportional to it's mass
F ma =
Newton's third Law
when one body exsets a force on a second body, the
↓
second body expects a force of equal size and
opposite direction on the first body.
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