AP Physics 1 - Review 03 - Rubric Scarborough High School SCIENCE 1
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SCIENCE 1
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SCIENCE 1
AP Physics 1: Review Packet 03 RUBRIC
Problem 1
(a)
Fw (or Fg or mg) is straight down
FN is straight up
Ff is straight to the left
Ff = ma
FN = mg
FN = mg > Ff
(b)
Fw (or Fg or mg) is straight down
FN is up-right perpendicular to plane
Ff is up-lef...
ap physics 1 review 03 rubric scarborough high school science 1
ap physics 1 review packet 03 rubric problem 1 a fw or fg or mg is straight down fn is straight up ff is straight to the
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AP Physics 1: Review Packet 03 RUBRIC
Problem 1 Problem 2
(a) (a) (c) Both trains have the same net force
Fw (or Fg or mg) is straight down The horse pulls the cart forward Both trains have the same net force
FN is straight up The cart moves forward Net force = mass acceleration
Ff is straight to the left The cart pulls backward on the horse Acceleration is the slope
Ff = ma The horse doesn’t go forward as Accel. is the slope of velocity vs. time
FN = mg quickly as it would without the cart Both graphs have the same slope
FN = mg > Ff Both graphs have the same accel.
(b) Slope is constant so acceleration is
(b) The heavy car pushes the light car constant
Fw (or Fg or mg) is straight down forward
FN is up-right perpendicular to plane The light car moves foward (d) Weight > Norm. and Tens. > Frict.
Ff is up-left parallel to plane The light car pushes the heavy car Weight is greater than normal
Ff = mgsin backward Tension is greater than friction
FN = mgcos The heavy car slows down There is one down force (weight)
mg > FN > Ff There are two up forces (normal and
(c) vertical component of tension)
The helicopter pushes down on the air Weight must be greater than normal
(c)
Fw (or Fg or mg) is straight down The air flows downward since weight balances two forces
FN is up-right perpendicular to plane The air pushes up on the helicopter Horizontal component of tension
Ff is down-right parallel to plane The helicopter remains above the equals friction
Fa is up-left parallel to plane ground Tension has a vertical component as
Fa = Ff + mgsin well
Problem 3 Tension has two components making
FN = mgcos (a) Spring stretches the same it bigger than friction
Weight is ranked highest Stretch of the spring is same in both
Friction is ranked lowest cases (e) Student C is correct
To change the stretch of the spring, Student C is correct
(d) the spring must apply a different force Student A is wrong: Forces can’t have
Fw (or Fg or mg) is straight down To apply a different force, the block the same length because the system is
FN is straight to the left (and/or elevator) must be accelerating. accelerating
Ff is straight up “Constant speed” means zero System is accelerating means forces
Fa is straight to the right acceleration. can’t balance
Fa = FN Zero acceleration in both cases, so the Student B is wrong: 2 kg slows down
Ff = mg spring exerts the same force in both Force opposing velocity is greater
Weight equals friction cases. than force with velocity if an object
Normal equals applied Therefore the stretch of the spring is slows down
FN and Fa greater than Fw and Ff the same. Student C is correct: 5 kg moves right
so friction must be to the left.
(e) (b) Linda would get pulled up off of the Friction opposes the direction the
Fw (or Fg or mg) is straight down ground block slides.
FN is straight up Linda would get pulled up off of the
mg – FN = mv2/r ground
mg > FN The barrel is heavier than she is
The Linda-Barrel system would have
(f) a net force causing the barrel to go
Fw (or Fg or GmM/r2) is straight left down and Linda to go up
GmM/r2 = mv2/r
Review Packet Belongs To: ______________________________ Grade: __________/100
Grader: ______________________________
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