Homework 6 Solutions - ALL ANSWERS ARE CORRECT - University of California, Los Angeles LIFESCIENC 30B
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Course
LIFESCIENC 30B mathmatics for life science
Institution
University Of California, Los Angeles
Homework 6 Solutions
Total points: 32
6.4.7: Show that M3 =
1 0
0 1
.
Solution:
M3 =
0 1
−1 −1
0 1
−1 −1
0 1
−1 −1
=
0 1
−1 −1
−1 −1
1 0
=
1 0
0 1
.
6.4.8: Using the point p =
5
0
as the test point, apply M three ti...
,6.4 FE 7: Compute the eigenvalues of the linear function
X 4X − 5Y
f( )=
Y 2X − 2Y
Solution: The matrix representation of this linear function is
4 −5
.
2 −2
The characteristic equation is
λ2 − 2λ + 2 = 0.
Therefore,
λ = 1 ± i.
−9 −8
6.4 FE 8: One of the eigenvalues of the matrix is 3. What is a corresponding eigen-
12 11
vector for it?
X −9 −8
Solution: Let’s denote by an arbitrary eigenvector with eigenvalue 3 of , so that
Y 12 11
−9 −8 X X
=3· .
12 11 Y Y
This gives you a system of two linear equations in X and Y , and you can solve the first or the
second equation to find that
3
Y = − X.
2
So, the vectors of the form
X
,
− 32 X
where X 6= 0, are the eigenvectors with eigenvalue 3 of this matrix. Letting X = 2, you can choose
as your particular eigenvector
2
V= .
−3
2
,
4 5 −3
6.4 FE 9: One of the eigenvalues of the matrix 4 6 −4, is 2. What is a corresponding
8 11 −7
eigenvector for it?
Solution: Let’s denote by
X
Y
Z
an arbitrary eigenvector with eigenvalue 2 of this matrix, so that
4 5 −3 X X
4 6 −4 Y = 2 · Y .
8 11 −7 Z Z
This gives you a system of three linear equations in X, Y, and Z, namely
4X + 5Y − 3Z = 2X
4X + 6Y − 4Z = 2Y
8X + 11Y − 7Z = 2Z
After simplification, you will find that
X = 2Y, Z = 3Y
(to get started, look at the coefficients of X). So, the vectors of the form
2Y
Y ,
3Y
where Y 6= 0, are the eigenvectors with eigenvalue 2 of this matrix. Letting Y = 1, you can choose
as your eigenvector
2
V = 1 .
3
6.4 FE 10:
a) Solve for a and b in the equation
2 −3 9
a +b =
5 1 14
9
b) Use your answer to part (a) to give the coordinates of with respect to the basis
14
2 −3
, .
5 1
3
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