solutions manual introduction to engineering thermodynamics
solutions manual introduction to engineering thermodynamics
introduction to engineering thermodynamics
solutions manual introduction to eng
Connected book
Book Title:
Author(s):
Edition:
ISBN:
Edition:
More summaries for
Solution Manual for Introduction to Engineering Thermodynamics by Richard E. Sonntag |Complete A+ Guide
Solutions Manual for Introduction to engineering thermodynamics by Richard E. Sonntag, Claus Borgnakke A+
Solution Manual for Introduction to Engineering Thermodynamics by Richard E. Sonntag |Complete
All for this textbook (5)
Written for
Engineering
All documents for this subject (395)
Seller
Follow
QuizMerchant
Reviews received
Content preview
, 2-1
CHAPTER 2
The correspondence between the problem set in this first edition versus the
problem set in the 5'th edition text. Problems that are new are marked new and
those that are only slightly altered are marked as modified (mod).
New Old New Old New Old
1 1 21 new 41 new
2 2 22 18 42 32
3 new 23 19 43 34
4 3 24 15 44 35
5 5 25 new
6 6 26 20
7 7 27 21
8 new 28 new
9 9 29 new
10 10 30 23
11 11 31 24
12 12 32 new
13 new 33 new
14 new 34 26
15 new 35 27
16 13 36 new
17 new 37 28mod
18 14 38 29
19 new 39 30
20 16 40 31
,2-2
2.1 The “standard” acceleration (at sea level and 45° latitude) due to gravity is
9.80665 m/s2. What is the force needed to hold a mass of 2 kg at rest in this
gravitational field ? How much mass can a force of 1 N support ?
Solution:
ma = 0 = F = F - mg F
F = mg = 2 9.80665 = 19.613 N g
F = mg => m
m = F/g = .80665 = 0.102 kg
2.2 A model car rolls down an incline with a slope so the gravitational “pull” in the
direction of motion is one third of the standard gravitational force (see Problem
2.1). If the car has a mass of 0.45 kg find the acceleration.
Solution:
ma = F = mg / 3
a = mg / 3m = g/3
= 9. = 3.27 m/s2 g
This acceleration does not depend on the mass of the model car.
2.3 A force of 125 N is applied to a mass of 12 kg in addition to the standard
gravitation. If the direction of the force is vertical up find the acceleration of the
mass.
Solution: x
Fup = ma = F – mg F
a = ( F – mg ) / m = F / m – g
= 125/12 – 9.807 g
m
= 0.61 ms-2
2.4 A car drives at 60 km/h and is brought to a full stop with constant deceleration in 5
seconds. If the total car and driver mass is 1075 kg find the necessary force.
, 2-3
Solution:
Acceleration is the time rate of change of velocity.
dV 60 1000
a= = = 3.33 m/s2
dt 3600 5
ma = F ;
Fnet = ma = 1075 3.333 = 3583 N
2.5 A 1200-kg car moving at 20 km/h is accelerated at a constant rate of 4 m/s2 up to
a speed of 75 km/h. What are the force and total time required?
2.6 A steel plate of 950 kg accelerates from rest with 3 m/s2 for a period of 10s. What
force is needed and what is the final velocity?
Solution:
Constant acceleration can be integrated to get velocity.
dV
a=
dt
=> dV = a dt => V = a t
F
V = a t = 3 10 = 30 m/s => V = 30 m/s
F = ma = 950 3 = 2850 N
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller QuizMerchant. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $15.99. You're not tied to anything after your purchase.
