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Introduction to Fluid Mechanics 6th Edition Janna Solutions Manual
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- Chamberlain College Of Nursing
Introduction to Fluid Mechanics 6th Edition Janna Solutions Manual. Instant delivery .
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www.nursylab.comwww.nursylab.com T E S T B A N K S E L L E R . C O MSolution Manual for
Introduction to Fluid Mechanics
Sixth Edition
Introduction to Fluid Mechanics is intended for use at the undergraduate level in a mechanical or civil
engineering or applied sciences curriculum. It is assumed that the students have a knowledge of calculus
and physics, so that learning to use mathematics to model physical principles in fluid mechanics proceeds
without much difficulty. The book is arranged into thirteen chapters and is written using SI units as well
as British gravitational units.
To exclude either of these unit systems from any fundamental area of study is difficult at this time,
although efforts have been made since the first decade of the 20th century to convert entirely to SI units.
This is a costly venture. A brief description of the engineering system, complete with a discussion of gc, is
also included (for illustrative purposes only).
Philosophy
In adding new material, I have tried to achieve an understandable presentation of fluid mechanics
from a practical viewpoint, without producing an encyclopedia. My emphasis is on learning principles
and on learning to apply the descriptive equations to real life problems.
Learning is enhanced when we use equations to mathematically model phenomena that we see and
interact with every day, such as a flow from a draining coffee pot, drag force exerted on a bicycle–rider
combination, or measuring viscosity of peanut butter. A strong emphasis is placed on solving practical
problems, which makes learning a visual experience, and provides the students with an introduction to
the types of problems they are likely to encounter in practice.
Problems
Each chapter concludes with a ‘‘Problems’’ section. The problems are arranged so that the easier ones
are presented first, which helps in building the students’ confidence and skill in learning the principles
involved. The more difficult problems then allow the students to analyze the topic in more detail. The
problems are designed to systematically improve the students’ ability to understand and apply the
equations of fluid mechanics to various practical problems
In addition, the end-of-chapter problems have been grouped together by topic. This feature makes it
easier to select and assign problems that pertain to the specific area under study. It will also be easier for
the students to review specific portions of the text by solving the pertinent problems.
Abbreviated Table of Contents
Chapter Title
1 Fundamental Concepts
2 Fluid Statics
3 Basic Equations of Fluid Mechanics
4 Dimensional Analysis & Dynamic Similitude
5 Flow in Closed Conduits
6 Flow Over Immersed Bodies
7 Flow in Open Channels
8 Compressible Flow
9 Turbomachinery
10 Measurements in Fluid Mechanics
11 The Navier-Stokes Equations
12 Inviscid Flow
13 Boundary Layer FlowTESTBANKSELLER.COM
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2Laboratory Experiments
The undergraduate laboratory experience is important when used to supplement the lecture course.
So in many instances, I have included descriptions of experimental devices and data obtained on them.
The equipment described is fairly common to a number of institutions. It is hoped that this will add
interest on the part of the student when mathematically modeling physical phenomena.
Internet Resources
End of chapter questions have been formulated that ask the student to look something up on the
internet. These are designed to allow the student to obtain relevant information and to do so quickly.
Doc to pdf Conversions
The solutions manual was prepared using an early version of Word, which later versions have
trouble interpreting correctly. The early version of Word will typeset equations directly without the use of
the Equation Editor. Converting such documents to pdf for this manual works successfully except when
a square root symbol appears. The square root of x, for example is rendered correctly when typed but
when converted to pdf, it may not be rendered correctly.
Coverage
A first course in fluid mechanics would typically cover Chapters 1 through 6 and perhaps Chapter 8.
An intermediate course in fluid mechanics might cover Chapters 7, 8, 10, and 11. A first course in
turbomachinery would cover Chapter 9, supplemented with information from other sources.
Regardless of how many times a manuscript is checked, the occasional mistake does seem to slip past,
and maddeningly so. The author invites readers to report any errors to the publisher, so that
misconceptions are not taught as truths. The author also invites readers’ comments, which will be
gratefully accepted as advice on how to improve the text.
William S. Janna
Memphis, TNTESTBANKSELLER.COM
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1-1CHAPTER 1
1.1 An object has a mass of 46 kg and weighs 450 N on a spring scale. Determine the
acceleration due to gravity at this location.
m = 46 kg, W = 450 N, g = W
m = 450
46 = 9.78 m/s2 1.2 Use the Appendix tables to find the conversion factor between gallons per
minute (gpm) to cubic feet per second (cfs or ft3/s).
gallons
minute • 3.785411784 x 10-3
2.8316846592 x 10-2 • 1 minute
60 s
gpm • 2.228 x 10-3 = ft3/s 1.3 What is the weight in N of 1 ft 3 of kerosene?
V— = 1 ft3; kerosene Appendix Table A-5, ρ = 0.823(1.94) slug/ft3;
W = mg = ρV—g = 0.823(1.94)(1)(32.2) = 5.14 lbf; W = 5.14(4.448) or
W = 22.9 N 1.4 What is the conversion factor between BTU/hr and horsepower? Use the
conversion factors from Appendix Table A.2 to determine the answer.
BTU
hr · 1 hr 3600 s · 1054
745.7 = 3.926 x 10-4 HP
(BTU/hr)
1.5 Water has a density of 1 000 kg/m 3. What is its density in lbm/ft3, slug/ft3, and
g/cm3?
ρ = 1 000 kg/m3 (SI); ρ = 1 000
16.01 = 62.5 lbm/ft3 ρ = 1 000
16.01(32.2) = 1.94 slug/ft3 ρ = 1 000
1 000 = 1 g/cm3 1.6 The density of Ocean Breeze Shampoo was determined by weighing an object of
known volume in air, and again by weighing it while submerged in the liquid. If
the object was a 4 cm diameter sphere made of aluminum (specific gravity = 2.7),
what is the expected weight of the object while submerged in the shampoo?
D = 4 cm — V = πD3
6 = π(0.04)3
6 = 3.35 x 10-5 m3
s = 2.7 for the al ρliq = 1 121 kg/m3 from the example
(sρw)object = 2.7(1 000) = 2 700 kg/m3TESTBANKSELLER.COM
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