Summary
Sumario ecuación de la recta tangente a una curva en un punto dado
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ecuación de la recta tangente a una curva en un punto dado
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luisardila
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F- cuacioin de la rectatangent
1) Derivar la fvnciin
2) Evalvarla en el punto dado para obteuerm
3) Haya reemplazando ✗ en la foreign original
y
,
ewe¥a%e¥a 4) Con m a 4. yl hadar la eueaiiinutilitanolo 19 formula pu
4=3×2-4×+1 ✗ 2
y= ✓ 25-1-21 ✗ =3
• = •
"?
U' = 6×-4 4=31212-4121+1 n' = 125-+21
1×125 25^12/-1×1
m= 6121-4 4=5 n' = -
✗
M= 8 y
' = -
×
y= ✓ 25-1312
"" '
( 25 -
x2 )
Pasa por 12,51 utienependiente 8
y' = -
✗ 4=4
✓ 25
'
M= 4- 41 -
✗
2
✗ Xi
-4-1×-31=4-4
-
m= -
(3)
✓ 25-1312
'
M=
y 5 -
✗ -2
m= -1
-41×+9-+4=4
81×-21=4-5 4
8×-16=4-5
-3-4×+254=4
8×-16+5=4
8×-11=4 9%-1
Y=×z¥1_
•
-1=2
f- f' 1 4
'=I¥ÉÉ 7*+6%+2-5
1¥
× =
a-
9=154-1 91--2-1
M= (2721-1
-23-5×+16-25
-
U= ¥ 1214+21212+1
'=*¥¥
a
mL-1--111=4-41
m= -3125
u
'=×¥zI2 7,1×-21=4 -1¥)
Derivadas exponenciales ylogaritmicas
exponential Las formulas vesaltadas aplican
✗ '
= exponencial Inde la base derivadad
: .
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