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CHEM 120 Unit 4 Midterm (GRADED A) Questions and Answers elaborations | 100% Correct Solutions $10.99   Add to cart
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CHEM 120 Unit 4 Midterm (GRADED A) Questions and Answers elaborations | 100% Correct Solutions
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CHEM 120 Unit 4 Midterm 1. The correct isotope symbol for the isotope containing 1 proton and two neutrons – He 2. Which are the elements with the following electronic configuration: 1s2 2s2 2p6 3s1 – Sodium 1s2 2s2 2p5- Fluorine 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 – Geremanium (Ge) 3. Provide 4...

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  • April 27, 2022
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CHEM 120 Unit 4 Midterm

1. The correct isotope symbol for the isotope containing 1 proton

and two neutrons – He


2. Which are the elements with the following electronic

configuration:

1s2 2s2 2p6 3s1 – Sodium


1s2 2s2 2p5- Fluorine


1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2 – Geremanium (Ge)

3. Provide 4 examples of substances with ionic bonds


LiF - Lithium Fluoride, LiCl - Lithium Chloride, LiBr – Lithium

Bromide, LiI - Lithium Iodide, Nacl,Calcium Nitrate

5. Name the following:

N2 S 3 - dinitrogen trisulfide


NaCl – Sodium Choloride

P4O10- Phosphorus pentoxide


NaNO3- Sodium nitrate


Cl2O3- Dichlorine trioxide


6. A gas is enclosed in a 10.0 L tank at 350 mm Hg pressure. If the

gas is pumped into a 23.00 L vessel, what is the new pressure

10.0 L×350 mmHg 10.0 × 350mmHg 3500 mmHg
= =
23.00 L 23.00 23


This study source was downloaded by 100000845689434 from CourseHero.com on 04-27-2022 12:56:34 GMT -05:00


https://www.coursehero.com/file/79913941/midterm-questions-docx/

, 152.173 mmHG




7. The molarity of a solution that contains 12.5 g of KClO3 in 3.2

liter of solution is

moles of solute
Molarity = ; K- 39.10 + Cl-35.45 + O-
volume of solution

16(3)-48; KClO 3= 122.55 g/mol

12.5 g×1 mol 12.5 mol
M= = = 0.102 mol
122.5 g 122.5

0.102mol
= 0.032 M
3.2 L




8. What other compound could also be added in order to make a

buffered solution with each of the following:

H3PO4 - H2PO3

CH3COOH - CH2 CO 2-

-
H2CO3 - HCO 2




9. Balance: C2 H 4 + O 2 → CO 2 + H2 O


First take a look at the equation and see how many elements there

are, in this case we have 3 different elements; Carbon, Hydrogen

and Oxygen. To balance the equation start off by balancing the




This study source was downloaded by 100000845689434 from CourseHero.com on 04-27-2022 12:56:34 GMT -05:00


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