100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
Previously searched by you
Exam (elaborations) CHEM 108 Module 5 Exam Answers- Portage Learning Exam Page 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below the following data table is obtained: 2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec) [N2O$12.39
Add to cart
Exam (elaborations) CHEM 108 Module 5 Exam Answers- Portage Learning Exam Page 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below the following data table is obtained: 2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec) [N2O
Exam (elaborations)
CHEM 108 Module 5 Exam Answers- Portage Learning
Exam Page 1 In the reaction of gaseous N2O5 to yield NO2 gas and O2 gas as shown below the following data table is obtained: 2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec) [N2O5] [O2] 0 0.200 M 0 300 0.182 M 0.009 M ...
exam elaborations chem 108 module 5 exam answers portage learning exam page 1 in the reaction of gaseous n2o5 to yield no2 gas and o2 gas as shown below the following data table is obtained 2 n2o5
Exam Page 1
In the reaction of gaseous N 2O5 to yield NO2 gas and O2 gas as shown below the following data table
is obtained:
2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec)[N2O5] [O2]
0 0.200 M 0
300 0.182 M 0.009 M
600 0.166 M 0.017 M
900 0.152 M 0.024 M
1200 0.140 M 0.030 M
1800 0.122 M 0.039 M
2400 0.112 M 0.044 M
3000 0.108 M 0.046 M
Complete the following three problems:
Using the [O2] data from the table show the calculation of the average rate over the measured time interval from 0 to 3000 secs.
the average rate over the measured time interval from 0 to 3000 secs.
Rate= [O2]/t= (0.046-0)/3000-0 = 1.53 x 10-5 mole/L.s
Using the [O2] data from the table show the calculation of the instantaneous rate late in the reaction (2400 secs to 3000 secs).
the instantaneous rate late in the reaction (2400 secs to 3000 secs)
Rate = [O]/t = (0.046-0.044)/3000-2400 = 3.33 x 10-6 mol/L.s
Explain the relative values of the average rate and the late instantaneous rate.
The late instantaneous rate is larger since the concentrations of reactants is higher during the earlier
stages of the reaction
-2.0 points
Instructor Comments
The late instantaneous rate is smaller since the concentrations of reactants is higher during the earlier stages of the reactionEXAM PAGE 1 Answer Key
In the reaction of gaseous N 2O5 to yield NO2 gas and O2 gas as shown below the following data table
is obtained:
2 N2O5 (g) → 4 NO2 (g) + O2 (g) Data Table #1 Time (sec)[N2O5] [O2]
0 0.200 M 0
300 0.182 M 0.009 M
600 0.166 M 0.017 M
900 0.152 M 0.024 M
1200 0.140 M 0.030 M
1800 0.122 M 0.039 M
2400 0.112 M 0.044 M
3000 0.108 M 0.046 M
Complete the following three problems:
Using the [O2] data from the table show the calculation of the average rate over the measured time interval from 0 to 3000 secs.
The average rate over the measured time interval from 0 to 3000 secs is:
rate = ∆[O2] / ∆t = (0.046 - 0) / 3000 - 0 = 1.53 x 10-5 mol/L•s
Using the [O2] data from the table show the calculation of the instantaneous rate late in the reaction (2400 secs to 3000 secs).
The late instantaneous rate over the measured time interval from 2400 to 3000 secs is:
rate = ∆[O2] / ∆t = (0.046 - 0.044) / 3000 - 2400 = 3.33 x 10-6 mol/L•s
Explain the relative values of the average rate and the late instantaneous rate.
The late instantaneous rate is smaller since the concentrations of reactants is lowest during the late stages of the reaction.
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller LectMillard. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $12.39. You're not tied to anything after your purchase.
