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Gizmos Student Exploration: Advanced Circuits
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Gizmos Student Exploration: Advanced Circuits Answer Key
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Name: Lee Arthur Date: March 20, 2021Student Exploration: Advanced Circuits
Directions: Follow the instructions to go through the simulation. Respond to the questions and
prompts in the orange boxes.
[Note to teachers and students: This Gizmo was designed as a follow-up to the Circuits Gizmo. We
recommend doing that activity before trying this one.]
Vocabulary: circuit breaker, equivalent resistance, fuse, Ohm’s law, parallel circuit, series circuit
Prior Knowledge Questions (Do these BEFORE using the Gizmo.)
1. What is the mathematical relationship between current, resistance, and
voltage?
The mathematical relationship between current (I), resistance (R), and voltage
(V), as described by Ohm’s Law, stated that I=V/R, which was further
manipulated into V=IR and R=V/I, depending on what value needed to be
calculated. This meant that the current that flowed in a circuit was directly
proportional to the applied voltage and was inversely proportional to the
resistance of the circuit. When the voltage was increased, the current
decreased. When the resistance was increased, the current decreased.
2. What is the equivalent resistance (total resistance) of the series circuit
shown at left?
G→ R1=10Ω R2=20Ω R3=100Ω
R→ RT
A→ RT=R1+R2+R3
S→ RT=10Ω+20Ω+100Ω
=130Ω
P→ The total resistance of the series circuit shown at the left was 130Ω.
Gizmo Warm-up
In the Circuits Gizmo, you learned how to use Ohm’s law:
I = V/R, to determine the current in parallel and series circuits. But how do
you find the resistance and current in a complex circuit that has both
series and parallel elements?
First, review how to find the equivalent resistance of a parallel circuit
Use the Advanced Circuits Gizmo to construct the parallel circuit shown at
right, using a 10-ohm and a 20-ohm resistor. Set the Selected battery
voltage to 20 volts.
Reproduction for educational use only. Public sharing or posting prohibited. © 2021 ExploreLearning™ All rights reserved
, 1. Move the Ammeter next to the battery. The current was 1.50amps when the Ammeter was placed
What is the current? next to the battery.
2. Based on Ohm’s law, what is the G→ V=10.00volts I=1.50amps
equivalent resistance in the circuit? R→ RT
A→ R=V/I
S→ R=10.00volts/1.50amps
=6.7Ω
P→ The total resistance in the circuit, based on Ohm’s law,
was 6.7Ω.
3. You can calculate the equivalent resistance of a parallel circuit using the following equation:
Based on this equation, what is the G→ R1=10Ω R2=20Ω
equivalent resistance of the circuit? R→ RT
A→ 1/RT=1/R1+1/R2
S→ 1/RT=1/10Ω+1/20Ω
=1/0.15Ω
=6.7Ω
P→ The total resistance of the circuit was 6.7Ω.
Activity A: Get the Gizmo ready:
Solving complex ● Click Clear to remove all components from the
circuits CIRCUIT BOARD.
Introduction: Solving a complex circuit may look difficult, but all you have to do is be patient and solve one
part of the circuit at a time. Use these two rules to find the resistance of a part of a circuit:
● For components connected in series, the equivalent resistance is the sum of the resistance of each
component: Rt = R1 + R2 + … + Rn.
● For resistors connected in parallel, use the equivalent resistance equation:
Goal: Determine the resistance and current in a circuit with
parallel and series elements.
1. Calculate: Use the Gizmo to create the circuit shown at right.
Next, find the equivalent resistance of the outlined parallel
component of the circuit. Show your work. (Hint: The lowest
common denominator of the three fractions is 60.)
Reproduction for educational use only. Public sharing or posting prohibited. © 2021 ExploreLear ning™ All rights reserved
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