Chapter 4 Solutions
An Introduction to Mathematical Thinking:
Algebra and Number Systems
William J. Gilbert and Scott A. Vanstone, Prentice Hall, 2005
Solutions prepared by William J. Gilbert and Alejandro Morales
Exercise 4-1:
Calculate the following. 5 3
Solution:
5 3 = 5 3 · · 4 2 ...
, By definition,
n+2 (n + 2)!
= .
n 2!n!
Hence, we must solve n2 + 3n + 2 = 72 or n2 + 3n + 70 = 0. By the quadratic
formula, we find n = 7 or n = −10.
Exercise 4-8:
Write the following in sigma notation.
1 3 5 99
+ + + ··· + .
2 4 6 100
Solution:
99
1 3 5 99 X r
+ + + ··· + = .
2 4 6 100 r=1 r + 1
Exercise 4-9:
Write the following in sigma notation.
8 + 15 + 24 + 35 + · · · + (n2 − 1).
Solution:
n
X
8 + 15 + 24 + 35 + · · · + (n2 − 1) = (r2 − 1).
r=3
Exercise 4-10:
Write the following in sigma notation.
ak + a2k + a4k + a8k + a16k + · · · + a256k
Solution:
8
X r
ak + a2k + a4k + a8k + a16k + · · · + a256k = a2 k .
r=0
Exercise 4-11:
Prove, by induction, the following results for all n ∈ P.
12 + 22 + 32 + · · · + n2 = n(n+1)(2n+1)
6 .
Solution:
1(1+1)(2·1+1) 6
(i) When n = 1 the assertion is true since 6 = 6 = 1.
4.3
, (ii) Suppose that
k(k + 1)(2k + 1)
12 + 22 + 32 + · · · + k 2 = .
6
Then
12 + 22 + 32 + · · · + k 2 + (k + 1)2
k(k + 1)(2k + 1) 6(k + 1)(k + 1)
= +
6 6
(k + 1)(k(2k + 1) + 6(k + 1)
=
6
(k + 1)(k(2k + 1) + 2(2k + 1) + 2(k + 2))
=
6
(k + 1)(k + 2)(2k + 1 + 2) (k + 1)(k + 2)(2(k + 1) + 1)
= = .
6 6
Hence the assertion is true for n = k + 1.
Therefore, by the principle of mathematical induction, the assertion is true
for all n ∈ P.
Exercise 4-12:
Prove, by induction, the following results for all n ∈ P.
2
3 3 3 3 n(n + 1)
1 + 2 + 3 + ··· + n =
2
Solution: h i2
(i) If n = 1, then 13 = 1(1+1)
2 . Hence the proposition is valid for n = 1.
h i2
(ii) Assume that 13 + 23 + · · · + k 3 = k(k+1)
2 for some k ∈ P. Then
k + 4k + 4
= (k + 1)2 = (k + 1)2
4 22
2
(k + 1)(k + 2)
= .
2
Thus the proposition is valid for n = k + 1. Therefore, by the principle of
mathematical induction, the proposition is true for all n ∈ P.
Exercise 4-13:
Prove by induction the following results for all n ∈ P.
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