CHEM 103 Exam 1 to 6 Questions With Correct Answers Latest Update, CHEM 103 Module 1 Exam Questions and Answers, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam & CHEM 103 Final Exam Questions and Answers Latest Update | Portage Learning.

1.18 moles of C9H8NO4Cl Grams = 1.18 moles X 229.614 = 270.944 grams --> 270.9 grams of C H NO Cl C = 9 x 12.01 = 108.09 H = 8 x 1.008 = 8.064 N = 1 x 14.01 = 14.01 O = 4 x 16.00 = 64 Cl = 1 x 35.45 = 35.45 Molecular Weight of C H NO Cl = 229.614 3 4 2 9 8 4 9 8 4 1. Grams = Moles x m...

Show the calculation of the molecular weight for the following compounds, reporting your answer to 2 places after the decimal. 1. Al2(CO3)3 2. C8H6NO4Cl 1. 2Al + 3C + 9O = 233.99 2. 8C + 6H + N + 4O + Cl = 215.59 Question 2 Click this link to access the Periodic Table. This may be helpful thr...

Classify each of the following as an element, compound, solution or heterogeneous mixture and explain your answer. 1. Barium chloride 2. Blood 3. Boron Answer: 1. Barium chloride - is not on periodic table (not element) - has two element names = Compound 2. Blood - is not on periodic table (n...

Show the calculation of the heat of reaction (ΔHrxn) for the reaction: 2 C2H6 (g) + 5 O2 (g) → 4 CO (g) + 6 H2O (l) by using the following thermochemical data: ΔHf 0 C2H6 (g) = -84.0 kJ/mole, ΔHf 0 CO (g) = -110.5 kJ/mole, ΔHf 0 H2O (l) = -285.8 kJ/mole Your Answer: 2 C2H6 (g) + 5 O2...