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MATH302 Week 6 Discussion; Hypothesis testing I and II Testing differences between means variances and proportions.docx
MATH302 Week 6 Discussion; Hypothesis testing I and II Testing differences between means variances and
- Other
- • 1 pages •
MATH302 Week 6 Discussion; Hypothesis testing I and II Testing differences between means variances and
MATH302 Week 5 Test
1. Question: The population standard deviation for the height of college football players is 2.7 inches. If we want to estimate a 95% confidence interval for the population mean height of these players with a 0.65 margin of error, how many randomly selected players must be surveyed? 2. Question: The population standard deviation for the height of college basketball players is 2.9 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.45...
- Exam (elaborations)
- • 15 pages •
1. Question: The population standard deviation for the height of college football players is 2.7 inches. If we want to estimate a 95% confidence interval for the population mean height of these players with a 0.65 margin of error, how many randomly selected players must be surveyed? 2. Question: The population standard deviation for the height of college basketball players is 2.9 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.45...
MATH302 Week 5 Test 5 Critique
MATH302 Week 5 Test 5 Critique
- Other
- • 2 pages •
MATH302 Week 5 Test 5 Critique
MATH302 Week 5 Knowledge Check Homework Practice Questions
1. Question: Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.68. How many customers should the company survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of true proportion of customers who click on ads on their smartphones? 2. Question: There is no prior information about the ...
- Exam (elaborations)
- • 20 pages •
1. Question: Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.68. How many customers should the company survey in order to be 97% confident that the margin of error is 0.29 for the confidence interval of true proportion of customers who click on ads on their smartphones? 2. Question: There is no prior information about the ...
MATH302 Week 5 Discussion; Confidence Intervals and Sample Size
Using the data set you collected in Week 1, excluding the super car outlier, you should have calculated the mean and standard deviation during Week 2 for price data. Along with finding a p and q from Week 3. Using this information, calculate two 95% confidence intervals. For the first interval you need to calculate a T-confidence interval for the sample population. You have the mean, standard deviation and the sample size, all you have left to find is the T-critical value and you can calculate ...
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- • 2 pages •
Using the data set you collected in Week 1, excluding the super car outlier, you should have calculated the mean and standard deviation during Week 2 for price data. Along with finding a p and q from Week 3. Using this information, calculate two 95% confidence intervals. For the first interval you need to calculate a T-confidence interval for the sample population. You have the mean, standard deviation and the sample size, all you have left to find is the T-critical value and you can calculate ...
MATH302 Week 4 Test
1. Question: A dishwasher has a mean life of 11.5 years with an estimated standard deviation of 1.5 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed. Find the number of years that the bottom 10% of dishwasher would last. Round answer to 2 decimal places. 2. Question: The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 47.8 cm and a s...
- Exam (elaborations)
- • 17 pages •
1. Question: A dishwasher has a mean life of 11.5 years with an estimated standard deviation of 1.5 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed. Find the number of years that the bottom 10% of dishwasher would last. Round answer to 2 decimal places. 2. Question: The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 47.8 cm and a s...
MATH302 Week 4 Test
1. Question: A dishwasher has a mean life of 11.5 years with an estimated standard deviation of 1.5 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed. Find the number of years that the bottom 10% of dishwasher would last. Round answer to 2 decimal places. 2. Question: The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 47.8 cm and a s...
- Exam (elaborations)
- • 17 pages •
1. Question: A dishwasher has a mean life of 11.5 years with an estimated standard deviation of 1.5 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed. Find the number of years that the bottom 10% of dishwasher would last. Round answer to 2 decimal places. 2. Question: The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 47.8 cm and a s...
MATH302 Week 4 Test 4 Critique
MATH302 Week 4 Test 4 Critique
- Other
- • 1 pages •
MATH302 Week 4 Test 4 Critique
MATH302 Week 4 Knowledge Check Homework Practice Questions
1. Question: Find the area under the standard normal distribution to the left of z = -1.05. Round answer to 4 decimal places. 2. Question: Arm span is the physical measurement of the length of an individual's arms from fingertip to fingertip. A man's arm span is approximately normally distributed with mean of 70 inches with a standard deviation of 4.5 inches. Find length in inches of the 99th percentile for a man's arm span. Round answer to 2 decimal places. 3. Question: Find P(-1.96 ≤ Z ...
- Other
- • 14 pages •
1. Question: Find the area under the standard normal distribution to the left of z = -1.05. Round answer to 4 decimal places. 2. Question: Arm span is the physical measurement of the length of an individual's arms from fingertip to fingertip. A man's arm span is approximately normally distributed with mean of 70 inches with a standard deviation of 4.5 inches. Find length in inches of the 99th percentile for a man's arm span. Round answer to 2 decimal places. 3. Question: Find P(-1.96 ≤ Z ...
MATH302 Week 4 Discussion; The normal distribution I and II
MATH302 Week 4 Discussion; The normal distribution I and II
- Other
- • 2 pages •
MATH302 Week 4 Discussion; The normal distribution I and II
NUR 514 Topic 6 Assignment; Emerging Technology Brief
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