Umd bsci 330 - Study guides, Class notes & Summaries

How does translation terminate? - ️️-stop codon (UAA, UAG,UGA) -instead of tRNA, release factor binds to ribosome, causing hydrolysis of the peptidyl tRNA, releasing the completed protein -ribosome dissociates into its subunits, releasing mRNA, release factor, and tRNA mRNA and protein synthesis are very energetically - ️️adding each subunit requires the conversion of an NTP to an NMP, equivalent to hydrolyzing 2 ATPS to ADP -elongation step consume multiple ATP/GTP -splicing and ...

the structure of secondary protein is dependent on? - ️️weak H-bonds b/t C=O & NH in backbone - NOT SIDE CHAINS the structure of beta sheet's is dependent on? - ️️H-bonding is between C=O & N-H on ADJACENT polypeptide chains with proteins, structure = - ️️function describe the structure of primary proteins - ️️-linear sequence of amino acid residue -determines mRNA structure the structure of primary amino acids is dependent on? - ️️covalent binds b/t amino acids in...

in condensation reactions, removing H2O ____. While adding H2O ____ - ️️in condensation reactions, removing H2O forms molecules. While adding H2O breaks down molecules. describe chemical feature(s) of amino acids - ️️uniform chemical structure w/ directionality - amino terminus -carboyl terminus -R group what is the difference between seeing and visualizing? - ️️seeing- can detect visualizing- seeing shapes, structures, measuring Given the following building blocks ==> s...

What are elongation factors? (transcription) - ️️use ATP hydrolysis to help RNA poly. move along chromatin -make sure RNA isnt falling off DNA/ skipping nucleotides Differences between eukaryotic and prokaryotic transcription - ️️- Euk: Have 3 different RNA polymerases. Pro: only one - Starting --- Euk: Needs general transcription factors to start transcription and position RNA polymerase. Pro: RNA polymerase binds to promoter sequence immediately. - Stopping --- Euk: Polyadenylat...

UMD BSCI 330 exam 2 Study Guide Solutions Protein Translation - ANSWER-20 different amino acids -triple nucleotide code= 64 different combinations codon - ANSWER-set of 3 nucleotides -most amino acids have multiple corresponding codons tRNA - ANSWER-matches amino acids with codons -amino acid is covalently attached to the 3' end of the tRNA -contains loop with an anticodon that is complementary to the appropriate amino acids codon Amino acid activation - ANSWER--first activated by co...

UMD BSCI 330 exam 1 Practice Questions and Answers what is the difference between seeing and visualizing? - ANSWER-seeing- can detect visualizing- seeing shapes, structures, measuring Given the following building blocks ==> structures sugar fatty acid amino acid nucleotides - ANSWER-sugar ==> polysaccharides fatty acid ==> fat, lipids, membranes amino acid ==> protein nucleotides ==> nucleic acid ©EMILLECT 2024/2025 ACADEMIC YEAR. ALL RIGHTS RESERVED FIRST PUBLISH OC...

UMD BSCI 330 exam 2 Practice Questions and Answers with proteins, structure = - ANSWER-function describe the structure of primary proteins - ANSWER--linear sequence of amino acid residue -determines mRNA structure the structure of primary amino acids is dependent on? - ANSWER-covalent binds b/t amino acids in linear sequence describe structure of secondary proteins - ANSWER--folding & twisting of peptide backbone -NO amino acid side chain interactions the structure of secondary protein ...

Information in DNA - ️️same as mRNA, transcription termination and initiation information, splicing information catalytic domain - ️️protein domain in enzyme-linked receptors, activated by a conformational change induced by the ligand-binding domain, inhibits host cell protein synthesis and interacts with substrate to cause enzyme reaction tRNA - ️️An RNA molecule that functions as an interpreter between nucleic acid and protein language by picking up specific amino acids and r...

UMD BSCI 330 Exam 2 (Part I) Questions and Answers what are some examples of the central dogma not applying to all cases of biological information - ANSWER-- retrovirus (RNA -> DNA) - b/c reverse transcription is used to create DNA Differences between eukaryotic and prokaryotic transcription - ANSWER-- Euk: Have 3 different RNA polymerases. Pro: only one - Starting --- Euk: Needs general transcription factors to start transcription and position RNA polymerase. Pro: RNA polymerase bind...