Mat 133 4 3 homework help - Study guides, Class notes & Summaries

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4-3 Homework Help MAT 133-J4254 | Questions with Solutions
  • 4-3 Homework Help MAT 133-J4254 | Questions with Solutions

  • Exam (elaborations) • 10 pages • 2023
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  • 4-3 Homework Help MAT 133-J4254 | Questions with Solutions. Suppose the probability of an IRS audit is 1.4 percent for U.S. taxpayers who file form 1040 and who earned $100,000 or more. (a) What are the odds that such a taxpayer will be audited? P(A) = P(the taxpayer will be audited): 1.4% → .014 P(A’) = P(the taxpayer won’t be audited) = 1 - .014 = .986 b) What are the odds against such a taxpayer being audited? Here is a video you can watch for Problem 2: Homework Problem 3 Reca...
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4-3 Homework Help | Questions with Solutions (MAT 133-J4254)
  • 4-3 Homework Help | Questions with Solutions (MAT 133-J4254)

  • Exam (elaborations) • 10 pages • 2023
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  • 4-3 Homework Help | Questions with Solutions (MAT 133-J4254) Currently Samsung ships 24.8 percent of the organic light-emitting diode (OLED) displays in the world. Let S be the event that a randomly selected OLED display was made by Samsung. a) Find P(S). b) Find P(S′). c) Find odds in favor of event S. d)Find odds against event S. a) Find P(S). This is a terminology/detail question. A probability must be a number between 0 and 1. If you are given a percent, you must move the decimal two...
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MAT 133 4-3 Homework Help | Questions with Solutions
  • MAT 133 4-3 Homework Help | Questions with Solutions

  • Exam (elaborations) • 10 pages • 2023
  • MAT 133 4-3 Homework Help | Questions with Solutions. So you need to multiply your individual probabilities together to see if it equals the probability of them both happening. Which pairs of events are independent? P(J) = .50, P(K) = .40, P(J ∩ K) = .3. P(J) ×P(K) = .5 ×.4 =.2 and P(J ∩ K) = .3, therefore J and K are not independent. P(J) = .60, P(K) = .20, P(J ∩ K) = .12. P(J) × P(K) = .6 ×.2 =.12 and P(J ∩ K) = .12, therefore J and K are independent. P(J) = .15, P(K) = .5,...
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MAT 133-J4254 | MAT 133 6-3 Homework Help | Assignment Solutions 2023 (MATH)
  • MAT 133-J4254 | MAT 133 6-3 Homework Help | Assignment Solutions 2023 (MATH)

  • Exam (elaborations) • 10 pages • 2023
  • Available in package deal
  • MAT 133-J4254 | MAT 133 6-3 Homework Help | Assignment Solutions 2023 (MATH) Students who score in the top 7 percent are recognized publicly for their achievement by the Department of the Treasury. Assuming a normal distribution, how many standard deviations above the mean does a student have to score to be publicly recognized? Normal Distribution: Top 7% is the same as the bottom 93% Using Excel you would use =NORM.S.INV(p) where p is the area to the left of the z-score. =NORM.S.INV(.93...
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