Derivative of tanx - Study guides, Class notes & Summaries

when is a curve convex - Answer gradient is decreasing (second derivative < 0 ) when is a curve concave - Answer gradient is increasing ( second derivative > 0 ) cosine rule - Answer a² = b² + c² - 2bcCosA area of triangle - Answer A=1/2absinC trig identity relating tanx and secx - Answer 1 + tan^2x = sec^2x trig identity relating cosecx and cotx - Answer 1 + cot^2x = cosec^2x arc length - Answer theta r arc area - Answer 1/2 theta r^2 f(|...

Derivative of sinx - correct answer Cosx Derivative of tanx - correct answer Sec^2x Derivative of secx - correct answer Secxtanx Derivative of cosx - correct answer -sinx Derivative of cotx - correct answer -csc^2x Derivative of cscx - correct answer ...

equation of a tangent line - ANSWER-y= f'(x)(x-x1)+f(x) difference quotient/ average rate of change (AROC) - ANSWER-f(x+h)-f(x)/h point slope form of a line - ANSWER-y-y1=m(x-x1) derivative is the same as... - ANSWER--slope of the tangent line -instantaneous rate of change -marginal (cost, profit, revenue) slope of the secant line - ANSWER-msec= (y2-y1)/(x2-x1) constant rule - ANSWER-if C is a real number, then the derivative of C =0 power rule - ANSWER-if n is a nonnegative...

Jacobian How to use the chain rule? When you have a composition of functions (dw/ds, dw/dt)= (df/du, df/dv)(du/ds, dv/ds, du/dt, dv/dt) so it gives a vector Classify critical points 1. differentiate WRT each variable x and y. 2. set them equal to 0. then solve for the values (often take the equation that is easy to factorize and take its values. 3. replace the values obtained in the other partial equation set equal to 0 to get the points ***trick: you can add the equations some...

Function - correct answer A rule that assigns "x" exactly one element called f(x). Lines - correct answer y=mx+b m=(y2-y1)/(x2-x1) Polynomial - correct answer A monomial or a sum or difference of monomials Rational Function - correct answer a ratio of polynomials Power Function - correct answer y...

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Test Bank for Calculus Early Transcendentals 9th Edition //Calculus: Early Transcendentals Ch3 Product Rule - CORRECT ANSW-d/dx [ u(x) v(x)] = u'(x) v(x) + u(x) v'(x) Quotient Rule - CORRECT ANSW-d/dx [u/v] = (vu'-uv')/v² Derivatives of Trig Functions - CORRECT ANSW-d/ dx [sinx] = cosx d/dx [ cosx] = -sinx d/dx [ tanx] = sec^2 x d/dx [cot] = -csc^2 x d/dx [ sec x] = secxtanx d/dx [ cscx] = -cscxcotx d/dx [arccotx] = -1/1+x^2 - CORRECT ANSW--1/1+x^2 ...

Calculus 1 Formula Sheet-Questions and Answers Graded A+ d/dx k - ANSWER-0 d/dx (mx+b) - ANSWER-m d/dx (x^n) - ANSWER-nx^n-1 d/dx [f(x)/g(x)] - ANSWER-g(x)f'(x)-f(x)g'(x)/g(x)^2 d/dx [f(x)+g(x)] (Sum Rule) - ANSWER-f'(x)+g'(x) d/dx (f(x)-g(x)) - ANSWER-d/dx f(x) - d/dx g(x) d/dx [f(x)g(x)] - ANSWER-f'(x)g(x)+f(x)g'(x) d/dx a^x - ANSWER-a^x ln(a) A function is not differentiable if - ANSWER-- discontinuity - corner (limit from left ≠ limit from right) - verti...