Chem 113 - Study guides, Class notes & Summaries
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Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update)
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Chem 103 Module 1 to 6 Exam with Verified answers (100 OUT OF 100) Portage learning (Latest Update) 
 
 
MODULE 1 EXAM 
Question 1	 Click this link to access the Periodic Table. This may be helpful throughout the exam. 
1.	Convert 845.3 to exponential form and explain your answer. 
2.	Convert 3.21 x 10-5 to ordinary form and explain your answer. 
 
 
1.	Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2.	Convert 3.21 x 10-5 = negative exponent = smalle...
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CSCC Chem 1113 exam 5/ HW 12,13,14 || with 100% Error-free Answers.
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Gluconeogenesis refers to the synthesis of glucose from noncarbohydrate sources. correct answers true 
 
Amino acids cannot be used to make glucose during gluconeogenesis. correct answers false 
 
Energy is released when ATP is converted to ADP. However, no energy is released when ADP is converted to AMP. correct answers false 
 
Consider the reaction shown below. What is the missing product? (Fill in the blank) 
Glucose + ATP -----> Glucose-6-phosphate + ______ correct answers ADP 
 
The mus...
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CHEM 113 Exam 1 CSU Q & A (2024)
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CHEM 113 Exam 1 CSU Q & A (2024)
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CHEM 113 CHAPTER 9 AND 10 PRACTICE QUESTIONS AND ANSWERS CORRECT SOLUTION LATEST UPDATE 2024
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1. Which of these properties is/are characteristics(s) of gases? 2. If the amount of a gas is tripled and the volume of the container is also tripled the new pressure of the gas will: 3. You’re at the zoo and have a big red 3.200 L helium balloon. The barometric pressure is 790.0 mm Hg. Then you hear the roar of a lion. Startled, you accidently release the balloon. It flies away. By the time it reaches the clouds the atmospheric pressure is only 0.3000 atm. What is the new volume of the balloo...
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CHEM 113 Homework #2, Chapter 2 complete solution University of Bridgeport
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CHEM 113 Homework #2, Chapter 2 complete solution University of Bridgeport
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Cscc Chem 1113 Exam 5/ Hw 12,13,14 Questions And Answers With Verified Solutions Well Elaborated!!!
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Cscc Chem 1113 Exam 5/ Hw 12,13,14 Questions And Answers With Verified Solutions Well Elaborated!!!
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Qualitative Analysis University Of Chicago CHEM 113
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Introduction: 
The purpose of this lab was to use qualitative analysis, or the testing of a substance or mixture to 
determine its chemical constituents, to identify the anions and cations of 14 unknown solutions. 
Identification was achieved by observing such things as physical appearance, appearance under a 
flame, pH levels, and reactions with other solutions. Qualitative analysis, as opposed to 
quantitative analysis, works only to determine the components of a mixture and does not regard 
t...
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CHEM 101 PRACTICE TEST COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS (ALREADY GRADED A+)
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CHEM 101 PRACTICE TEST COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS (ALREADY GRADED A+) 
The nucleus of an atom contains: 
A) Protons and electrons 
B) Protons and neutrons 
C) Electrons and neutrons 
D) Protons, neutrons and electrons 
E) Electrons only - Answer-B 
 
The nucleus of an atom contains protons and neutrons. 
 
Which subatomic particle is found in the nucleus and has no charge? 
A) Electron 
B) Neutron 
C) Proton 
D) Positron - Answer-B 
 
Neutrons are subatomic particles found i...
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CSM CHEM 210 Final Exam Questions and Correct Answers, With Complete Solution 2024.
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CSM CHEM 210 Final Exam Questions and Correct Answers, With Complete Solution 2024. 
 
If the fuel efficiency of an automobile is 22 miles per gallon, what is its fuel efficiency in Kilometers per liter? ( 1Km= 0.621 mile, 1.00 L=1.057 quarts and 4 quarts = 1 gallon) 
9.4 Km/L 
*What is the correct answer to the following expression: 
(49.1 - 42.61 ) x 13.1? 
85 
An intensive property of a substance is independent of amount. 
True 
Lithium has two stable isotopes with masses of 6.01512 amu and 7...
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CHEM 103 FINAL EXAM
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CHEM 103 FINAL EXAM.Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Do the conversions shown below, showing all work: 
1. 246oK = ? oC 
2. 45oC = ? oF 
3. 18oF = ? oK 
1. 246oK - 273 = -27 oC oK → oC (make smaller) 
-273 
2. 45oC x 1.8 + 32 = 113 oF oC → oF (make larger) x 1.8 + 32 
3. 18oF - 32 ÷ 1.8 = -7.8 + 273 = 265.2 oK oF → oC → oK 
Question 3 Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the ca...
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