Chem 120 final exam 4 - Study guides, Class notes & Summaries

CHEM 120 Week 8 Final Exam Questions-Answers (Version 1) 2023 UPDATE6. (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Points : 5) 7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Points : 5) 8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G ...

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CHEM 120 Week 8 latest Final Exam Jan 2023 COMPLETE WITH SOLUTIONS A+Question: The name of the compound FES04 is Question: Peptide bonds link the amino acids together to make a primary polypeptide sequence. The bonds are Question: If a balloon is filled with helium were heated with a blow dryer , the balloon would Question: You are setting up an experiment to test a pair of experimental headache medications, X & Y . As part of the experiment setup, you take individuals suffering from headache...

CHEM 120 Week 8 Final Exam - Question Only – Download For Revision Page 1 1. Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): 2. Question: (TCO 1) How many mL are in 3.5 pints? Show your work. 3. Question: (TCO 3) What is the name of the following compound: Zn3P2? 4. Question: (TCO 3) What is the name of the following compound: AgNO3? 5. Question: (TCO 6) Calculate the pressure, in atmospheres, of 2.78 ...

CHEM 120 WEEK 8 FINAL EXAM 2023 with A+ Grade Solutions 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3.5 pints is equivalent to 1656.116 1 pint = 473.176 ml 3.5 pints* 473.176mL = 1656.116mL 3. (TCO 3) What is the name of the following compound: Zn3P2? (Points : 5) It's Zinc P...

CHEM 120 WEEK 8 FINAL EXAM 2023 with A+ Grade Solutions 1. (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Points : 5) 2. (TCO 1) How many mL are in 3.5 pints? Show your work. (Points : 5) 3.5 pints is equivalent to 1656.116 1 pint = 473.176 ml 3.5 pints* 473.176mL = 1656.116mL 3. (TCO 3) What is the name of the following compound: Zn3P2? (Points : 5) It's Zinc P...

CHEM 14C Winter 12 Final Exam Part B Solutions 1. HO O O 2. Influence #1: Resonance causes some or the entire molecule to be planar. Influence #2: Resonance increases stability. Influence #3: Resonance causes electron delocalization. 3. Coplanar The carboxylic acid and ring B have this geometry because it allows for conjugation between the C=O and the B ring aromatic electron cloud. H 4. 5. Ten 6. A, B, and C 7. Of the carbon stereocent...

Week 10 Final Exam Return to deck 1. In AR disorders, carriers have:  Two mutated genes; two from one parent that cause disease  A mutation on a sex chromosome that causes a disease  A single gene mutation that causes the disease  One copy of a gene mutation but not the disease 2. A 76-year-old patient with a 200-pack year smoking history presents with complaints of chronic cough, dyspnea, fatigue, hemoptysis, and weight loss over the past 2 months. The physical exam re...

CHEM 14C Winter 12 Final Exam Part B Solutions 1. HO O O 2. Influence #1: Resonance causes some or the entire molecule to be planar. Influence #2: Resonance increases stability. Influence #3: Resonance causes electron delocalization. 3. Coplanar The carboxylic acid and ring B have this geometry because it allows for conjugation between the C=O and the B ring aromatic electron cloud. H 4. 5. Ten 6. A, B, and C 7. Of the carbon stereocent...