Harr clinical chemistry - Study guides, Class notes & Summaries
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Harr: Clinical Chemistry Questions And Answers With Complete Solutions
- Exam (elaborations) • 401 pages • 2023
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Which formula correctly describes the relationship between absorbance and %T ? 
 
A. A = 2 - log %T 
B. A = log 1/T 
C. A = -log T 
D. All of these options correct answer: D. All of these options 
 
D Absorbance is proportional to the inverse log of transmittance. 
A = -log T = log 1/T 
Multiplying the numerator and denominator 
by 100 gives: 
A = log (100/100 X T) 
100 X T = %T, 
substituting %T for 100 X T gives: 
A = log 100/%T 
A = log 100 - log %T 
A = 2.0 - log %T 
For example, if %T = 1...
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HARR CLINICAL CHEMISTRY 2024-2026 UPDATED VERSION ALL QUESTIONS AND CORRECT DETAILED ANSWERS WITH RATIONALES/ ALREADY GRADED A+/100%PASS.
- Exam (elaborations) • 377 pages • 2024
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HARR CLINICAL CHEMISTRY UPDATED VERSION ALL QUESTIONS AND CORRECT DETAILED ANSWERS WITH RATIONALES/ ALREADY GRADED A+/100%PASS.
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Harr: Clinical Chemistry 2024 Actual Questions and Answers 100% Solved
- Exam (elaborations) • 306 pages • 2024
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Which formula correctly describes the relationship between absorbance and %T ? 
A. A = 2 - log %T 
B. A = log 1/T 
C. A = -log T 
D. All of these options - D. All of these options 
D Absorbance is proportional to the inverse log of transmittance. 
A = -log T = log 1/T 
Multiplying the numerator and denominator 
by 100 gives: 
A = log (100/100 X T) 
100 X T = %T, 
substituting %T for 100 X T gives: 
A = log 100/%T 
A = log 100 - log %T 
A = 2.0 - log %T 
For example, if %T = 10.0, then: 
A = 2.0 ...
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Harr: Clinical Chemistry Exam Practice Questions and Answers
- Exam (elaborations) • 429 pages • 2024
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Harr: Clinical Chemistry Exam Practice 
Questions and Answers 
Which formula correctly describes the relationship between absorbance and %T ? 
A. A = 2 - log %T 
B. A = log 1/T 
C. A = -log T 
D. All of these options - ANSWER-D. All of these options 
D Absorbance is proportional to the inverse log of transmittance. 
A = -log T = log 1/T 
Multiplying the numerator and denominator 
by 100 gives: 
A = log (100/100 X T) 
100 X T = %T, 
substituting %T for 100 X T gives: 
A = log 100/%T 
Copyright ©...
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Harr: Clinical Chemistry Questions And Answers
- Exam (elaborations) • 481 pages • 2024
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Harr: Clinical Chemistry Questions And Answers
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Harr: Clinical Chemistry Exam Practice Questions and Answers 100% Pass
- Exam (elaborations) • 31 pages • 2024
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Harr: Clinical Chemistry Exam Practice 
Questions and Answers 100% Pass 
Select the most appropriate adult reference range for fasting blood glucose. 
A. 40-105 mg/dL (2.22-5.82 mmol/L) 
B. 60-140 mg/dL (3.33-7.77 mmol/L) 
C. 65-99 mg/dL (3.61-5.50 mmol/L) 
D. 75-150 mg/dL (4.16-8.32 mmol/L) - ANSWER-C. 65-99 mg/dL (3.61-5.50 mmol/L) 
C Reference ranges vary slightly depending upon method and specimen type. Enzymatic methods 
specific for glucose have an upper limit of normal no greater than 99 ...
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