TEST BANK FOR Fundamentals of Physics 7th Edition David Halliday, Robert Resnick, Jearl Walker

1. Using the given conversion factors, we find (a) the distance d in rods to be (4.0 furlongs)(201.168 m furlong) 4.0 furlongs = 160 rods, 5.0292 m rod d= = (b) and that distance in chains to be (4.0 furlongs)(201.168 m furlong) 40 chains. 20.117 m chain d= = 2. The conversion factors 1 gry =1/10 line , 1 line=1/12 inch and 1 point = 1/72 inch imply that 1 gry = (1/10)(1/12)(72 points) = 0.60 point. Thus, 1 gry2 = (0.60 point)2 = 0.36 point2, which means that 0.50 gry2= 0.18 point2 ...