100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Complete Solution Manual Fundamentals of Physics Extended 10th Edition Halliday Questions & Answers with rationales $16.19   Add to cart

Exam (elaborations)

Complete Solution Manual Fundamentals of Physics Extended 10th Edition Halliday Questions & Answers with rationales

 4 views  0 purchase
  • Course
  • Fundamentals of physics, 10th ed by Halliday
  • Institution
  • Fundamentals Of Physics, 10th Ed By Halliday

Fundamentals of Physics Extended 10th Edition Halliday Solutions Manual Complete Solution Manual Fundamentals of Physics Extended 10th Edition Halliday Questions & Answers with rationales PDF File All Pages All Chapters Grade A+ Fundamentals of Physics Extended 10th Edition Halliday Solutions Manua...

[Show more]

Preview 4 out of 1688  pages

  • November 9, 2024
  • 1688
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers
book image

Book Title:

Author(s):

  • Edition:
  • ISBN:
  • Edition:
  • Fundamentals of physics, 10th ed by Halliday
  • Fundamentals of physics, 10th ed by Halliday
avatar-seller
Labsolutions
TEST BANK For Fundamentals of Physics
10th Edition By Resnick, Walker and Halliday
Chapters 1 - 44

,Chapter 1 b




1. VariousbgeometricbformulasbarebgivenbinbAppendixbE.

(a) ExpressingbthebradiusbofbthebEarthbas

Rb b 6.37b b106b m103b kmb mb b 6.37b b103b km,

itsbcircumferencebisb sbb2bRb b2b(6.37bb103b km)bb4.00b104b km.

(b) ThebsurfacebareabofbEarthbisbAbb4bR2 b 4b 6.37bb103bbkm  b 5.10b b108 km2.
2




R bbbb  6.37bb103bbkm  b1.08bb1012bbkm 3 .
4bb 3 4b 3bbb
(c)bThebvolumebofbEarthbisb Vb b
3 3

2. Theb conversionb factorsb are:b1bgrybb1/10 b line b,b 1bline bb1/12 b inch bandb 1b pointb =b 1/72b
inch.bThebfactorsbimplybthat

1bgryb=b(1/10)(1/12)(72bpoints)b=b0.60bpoint.

Thus,b 1b gry2b =b (0.60b point)2b =b 0.36b point2,b whichb meansb thatb0.50 b gry 2 b=b 0.18 b point 2 b.

3. Thebmetricbprefixesb(micro,bpico,b nano,b …)bareb givenb forb readyb referenceb onb theb insideb
frontbcoverbofbthebtextbookb(seebalsobTableb1–2).

(a)bSinceb1bkmb=b1bb103bmbandb1bmb=b1bb106bm,

1kmb b 103b mb b 103b m106 bmb mbb109 m.

Theb givenb measurementb isb 1.0b kmb (twob significantb figures),b whichb impliesb ourb resultb
shouldbbebwrittenbasb1.0bb109bm.

(b)bWebcalculatebthebnumberbofbmicronsbinb1bcentimeter.bSinceb1bcmb=b102bm,

1cmb =b 102b m b =b 102m106b bmb mb b 104 m.

Webconcludebthatbthebfractionbofbonebcentimeterbequalbtob1.0bmbisb1.0bb104.b(

c)bSinceb1bydb=b(3bft)(0.3048bm/ft)b=b0.9144bm,


1

,
, 2 CHAPTERb1



1.0bydb =b 0.91m106b bmb mbb 9.1bb105 m.

4. (a)b Usingb theb conversionb factorsb 1b inchb =b 2.54b cmb exactlyb andb 6b picasb =b 1b inch,b web
obtain  b6b picasbb
0.80b cmb =b 0.80b cmb b 1binch  b  b1.9b picas.
2.54b cmb 1binchb 
   
(b)bWithb12bpointsb=b1bpica,bwebhave


0.80bcmb=b 0.80bcmb b 1binch   bbb12b pointsbb
bb6b picasb
2.54b cmb 1binchb 1bpica  b 23b points.
   


5. Givenbthatb1bfurlong b 201.168bmb,b1brodbb5.0292bm andb1bchainbb20.117b mb,b webfind
thebrelevantbconversionbfactorsbtobbe
1brod
1.0b furlongb b201.168bmbb(201.168bmb) b 40b rods,
5.0292 m
and
1bchain
1.0b furlongb b201.168b mb b (201.168b mb) 10b chainsb.
20.117bm
Noteb theb cancellationb ofb mb (meters),b theb unwantedb unit.b Usingb theb givenb conversionb
factors,bwebfind

(a) thebdistancebdbinbrodsbtobbe
40brods
db b 4.0bfurlongsb 4.0bfurlongsb b160b rods,
1bfurlong

(b) andbthatbdistancebinbchainsbtobbe

10bchainsb
db b 4.0b furlongsb 4.0bfurlongs b 40b chains.
1bfurlong

6. WebmakebusebofbTableb1-6.

(a) Weblookbatbthebfirstb(“cahiz”)bcolumn:b1bfanegabisbequivalentbtobwhatbamountbofbcahiz?b
Webnotebfrombthebalreadybcompletedbpartbofbthebtablebthatb1bcahizbequalsbabdozenbfanega.b
2
b cahiz,borb8.33bb10 bcahiz.b Similarly, b“1bcahizb =b48bcuartilla”b (inbthe
1
Thus,b1bfanegab=b 12
alreadybcompletedbpart)bimpliesbthatb1bcuartillab= 1bcahiz,48borb2.08bb 102b cahiz.bContinuin
b




gb inb thisb way,b theb remainingb entriesb inb theb firstb columnb areb 6.94b b 103b and
3.47103b.

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller Labsolutions. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $16.19. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

78252 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$16.19
  • (0)
  Add to cart