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Hand Bending Module 26107 Exam |Questions with Answers

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Hand Bending Module 26107 Exam |Questions with Answers

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  • November 7, 2024
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Hand Bending Module 26107 Exam |
Questions with Answers
Which of the following should be used to cut EMT? - -Hacksaw

- A die is used to - -cut threads in conduit

- Which of the following eliminates wrinkling or flattening when bending
PVC? - -Plug Set

- The Raidus of a circle is defied as - -The distance from the center point to
the edge of the circle

- Which of the following can be used to bend IMC - -A hickey

- A pocket knife can be used to deburr - -PVC

- The formula pi x D is used to calculate - -circumference

- two junction boxes are each located on different walls, 12 inches from the
same corner. Given a 90* bend with a take-up of 6 inches and a gain 2-1/4
inches, what is the developed length of the conduit between them? - -21-3/4
Formula: 12'' + 12" - 2 & 1/4 = 21 & 3/4

- Two 90 degree bends with a straight section of conduit between them
constitute a(n) ____ bend. - -back to back bend

- When creating an offset using 10 degree bends (with a multiplier of 6) to
cross a 6 inch obstruction, the distance between bends is - -36 inches

- Which of the following is most commonly used to cut RMC and IMC - -Pipe
Cutter

- Which of the following describes circumference - -Distance around circle

- A right triangle is any triangle with one - -90 degree angle

- Gain is best described as the - -Distance saved by the arc of a 90 degree
bend

- The developed length of a bend is equal to the - -Sum of the horizontal
and vertical distances minus the gain

-

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