UCF Foundation Exam (Computer
Science) Questions And Answers
Latest Update
Injective Function (one-to-one) Answer: f(a) = f(b)->(a=b) for all a & b in
domain f
Never more than one incoming arrow, but not always an arrow from left to all
of right values
If A->B then |A|<=|B|
Surjective (onto) Answer: For all b in B, there exists an a in A such that
f(a) = b
Multiple arrows can go to an answer on the right, and every value on right will
have an arrow going to it.
if A->B then |A|>=|B|
Bijective Answer: Both injective and Surjective. One-to-one and only
functions have inverses if A->B then |A|=|B|
What value is in every set Answer: Null
Assume: p, p->q
Then q Answer: Modus Ponens
, Assume p->q, q->r
Then p->r Answer: Law of syllogism
Assume p->q, -p
Then -q Answer: Modus tollens
A|B and A|C implies Answer: A|(B+C)
A = Bn + R Answer: A = R(mod B)
reflexive Answer: aRa for every element a in A
Irreflexive Answer: a does not Ra for every element a in A
Symmetric Answer: if aRb -> bRa for all a, b in A
Antisymmetric Answer: if aRb and bRa -> a=b for all a,b in A
Transitive Answer: if aRb & bRc -> aRc for all a,b,c in A
[x] = {a|a is an element of A ^ aRx} is an example of: Answer: Equivalence
classes
Best: O(1)
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