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FS Fourth Edition Session 2 Exam Questions & Answers 2024/2025

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FS Fourth Edition Session 2 Exam Questions & Answers 2024/2025 A 1000 ft long earthen berm has a cross section with an area of 1500 ft² at one end and 2000 ft² at the other end, with area increasing at a constant rate. What is the approximate volume of material in the berm? - ANSWERSV = l((A...

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  • October 3, 2024
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  • 2024/2025
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  • FS Fourth Edition Session 2
  • FS Fourth Edition Session 2
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FS Fourth Edition Session 2 Exam
Questions & Answers 2024/2025

A 1000 ft long earthen berm has a cross section with an area of 1500 ft² at one end and 2000 ft² at the
other end, with area increasing at a constant rate. What is the approximate volume of material in the
berm? - ANSWERSV = l((A1 +A2)/2)

= (1000)((1500+2000)/2)

= 1,750,000 ft²



1,750,00 ft²/(27/1) = 64,815 yd³



Which of the following is the best definition of mean sea level? - ANSWERSThe average of all the water
heights over a tidal epoch



On a topographic map, which of the following is correct? - ANSWERSContour lines crossing streams form
V's that point upstream



What is the effect on the location of a coastal boundary when natural and gradual changes occur to the
shoreline? - ANSWERSThe boundary changes with the changing shoreline

(accretion or erosion)



Choose the correct option for the underlined words in the following sentence: "He presented an
explanation as to how temperature affects distance measurements and what effect this has on the
accuracy of the survey." - ANSWERSNo change is necessary



What is the sum of matrices A and B?



A = [4 2] B=[1 5]

3 5 3 2 - ANSWERSA = [ 4 2 ] B = [ 1 5 ]

3532

, A+B = [4+1 2+5]

3+3 5+2

=[57]

67



What is the product of matrices A and B?



A = [4 2] B=[1 5]

3 5 3 2 - ANSWERSAB = [ (4)(1) + (2)(3) (4)(5) + (2)(2)]

(3)(1) + (5)(3) (3)(5) + (5)(2)



= [ 10 24 ]

18 25



In a traverse with a total length of 2180.91 m, one course has a latitude of 380.00 m and a departure of
0.00 m. The closure of the traverse in latitude is 0.042 m and in departure is 0.145 m. What is the
adjusted latitude and departure for that course if a compass rule adjustment is used? - ANSWERSlat adj=
= (course dist./total dist.)(lat error)

=(380.00/2180.91)(0.042)

=0.007 m



depart adj = (course dist/total dist.)(depart erro)

= (380.00/2180.91)(0.145)

=0.025 m



380.00 - 0.007 = 379.993 (adj. lat)



What is the arc length of a horizontal curve with coordinates as shown and a radius of 1000.0 ft? All
distances are in feet.

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