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TEST BANK FOR CAMPBELL BIOLOGY 12TH EDITION || CHAPTERS 6-10||FULL PACKAGE||LATEST

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  • September 27, 2024
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TEST BANK FOR CAMPBELL BIOLOGY 12TH EDITION
|| CHAPTERS 6-10||FULL PACKAGE||LATEST
Campbell's Biology, 9e (Reece et al.)
Chapter 6 A Tour of the Cell

This chapter introduces the topics of microscopy and cell fractionation, followed by a review of the cell
and the major organelles and structures of eukaryotic cells. A challenge with this chapter is to keep this
data from simply being a list of parts. In addition to the structure and function of individual organelles,
questions probe student understanding of the cell as a dynamic, interconnected system: the flow of
membrane and proteins in the endomembrane system to the plasma membrane; the flow of
information from the nucleus to the cytoplasm; and the connection between the cytoskeleton, the
plasma membrane, and the extracellular matrix. An evolutionary perspective goes beyond structural
distinctions between prokaryotes and eukaryotes to examine theories concerning the evolutionary
origins of eukaryotes and key eukaryotic cell structures.

Multipl

✔✔ - ANSWER - Answer: C
Topic: Concept 6.1

Skill: Knowledge/Comprehension

2) The advantage of light microscopy over electron microscopy is that
A) light microscopy provides for higher magnification than electron microscopy.
B) light microscopy provides for higher resolving power than electron microscopy.
C) light microscopy allows one to view dynamic processes in living cells.
D) light microscopy provides higher contrast than electron microscopy.
E) specimen preparation for light microcopy does not produce artifacts.

✔✔ - ANSWER - Answer: C
Topic: Concept 6.1

Skill: Knowledge/Comprehension

3) A primary objective of cell fractionation is to
A) view the structure of cell membranes.
B) sort cells based on their size and weight.
C) determine the size of various organelles.

,ESTUDY


D) separate the major organelles so that their particular functions can be determined.
E) separate lipid-soluble from water-soluble molecules.

✔✔ - ANSWER - Answer: D
Topic: Concept 6.1

Skill: Knowledge/Comprehension



4) In the fractionation of homogenized cells using centrifugation, the primary factor that determines
whether a specific cellular component ends up in the supernatant or the pellet is
A) the relative solubility of the component.
B) the size and weight of the component.
C) the percentage of carbohydrates in the component.
D) the presence or absence of nucleic acids in the component.
E) the presence or absence of lipids in the component.

✔✔ - ANSWER - Answer: B
Topic: Concept 6.1

Skill: Knowledge/Comprehension
5) Which of the following correctly lists the order in which cellular components will be found in the
pellet when homogenized cells are treated with increasingly rapid spins in a centrifuge?
A) ribosomes, nucleus, mitochondria
B) chloroplasts, ribosomes, vacuoles
C) nucleus, ribosomes, chloroplasts
D) vacuoles, ribosomes, nucleus
E) nucleus, mitochondria, ribosomes

✔✔ - ANSWER - Answer: E
Topic: Concept 6.1

Skill: Application/Analysis

6) Green fluorescent protein (GFP) can be used to fluorescently label a specific protein in cells by
genetically engineering cells to synthesize the target protein fused to GFP. What is the advantage of
using GFP fusions to visualize specific proteins, instead of staining cells with fluorescently labeled probes
that bind to the target protein?
A) GFP fusions enable one to track changes in the location of the protein in living cells; staining usually
requires preserved cells.
B) GFP fusions enable higher resolution than staining with fluorescent probes.

,ESTUDY


C) GFP permits the position of the protein in the cell more precisely than fluorescent probes.
D) GFP permits visualization of protein-protein interactions; fluorescent probes do not.
E) GFP fusions are not subject to artifacts; fluorescent probes may introduce background artifacts.

✔✔ - ANSWER - Answer: A
Topic: Concept 6.1

Skill: Application/Analysis

7) What is the reason that a modern electron microscope (TEM) can resolve biological images to the
subnanometer level, as opposed to tens of nanometers achievable for the best super-resolution light
microscope?
A) The focal length of the electron microscope is significantly longer.
B) Contrast is enhanced by staining with atoms of heavy metal.
C) Electron beams have much shorter wavelengths than visible light.
D) The electron microscope has a much greater ratio of image size to real size.
E) The electron microscope cannot image whole cells at one time.

✔✔ - ANSWER - Answer: C
Topic: Concept 6.1

Skill: Application/Analysis

8) What technique would be most appropriate to use to observe the movements of condensed
chromosomes during cell division?
A) light microscopy
B) scanning electron microscopy
C) transmission electron microscopy
D) confocal fluorescence microscopy
E) super-resolution fluorescence microscopy

✔✔ - ANSWER - Answer: A
Topic: Concept 6.1

Skill: Synthesis/Evaluation

9) All of the following are part of a prokaryotic cell except
A) DNA.
B) a cell wall.
C) a plasma membrane.
D) ribosomes.

, ESTUDY


E) an endoplasmic reticulum.

✔✔ - ANSWER - Answer: E
Topic: Concept 6.2

Skill: Knowledge/Comprehension

10) The volume enclosed by the plasma membrane of plant cells is often much larger than the
corresponding volume in animal cells. The most reasonable explanation for this observation is that
A) plant cells are capable of having a much higher surface-to-volume ratio than animal cells.
B) plant cells have a much more highly convoluted (folded) plasma membrane than animal cells.
C) plant cells contain a large vacuole that reduces the volume of the cytoplasm.
D) animal cells are more spherical, whereas plant cells are elongated.
E) plant cells can have lower surface-to-volume ratios than animal cells because plant cells synthesize
their own nutrients.

✔✔ - ANSWER - Answer: C
Topic: Concept 6.2

Skill: Synthesis/Evaluation

11) A mycoplasma is an organism with a diameter between 0.1 and 1.0 µm. What does the organism's
size tell you about how it might be classified?
A) It must be a single-celled protist.
B) It must be a single-celled fungus.
C) It could be almost any typical bacterium.
D) It could be a typical virus.
E) It could be a very small bacterium.

✔✔ - ANSWER - Answer: E
Topic: Concept 6.2

Skill: Application/Analysis

12) Which of the following is a major cause of the size limits for certain types of cells?
A) limitation on the strength and integrity of the plasma membrane as cell size increases
B) the difference in plasma membranes between prokaryotes and eukaryotes
C) evolutionary progression in cell size; more primitive cells have smaller sizes
D) the need for a surface area of sufficient area to support the cell's metabolic needs
E) rigid cell walls that limit cell size expansion

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