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CEM 141_ Stoichiometry (1). Questions & 100% Verified Correct Answers with complete solutions (Latest update $7.99   Add to cart
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CEM 141_ Stoichiometry (1). Questions & 100% Verified Correct Answers with complete solutions (Latest update

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CEM 141_ Stoichiometry (1). Questions & 100% Verified Correct Answers with complete solutions (Latest update

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  • August 15, 2024
  • 2
  • 2024/2025
  • Exam (elaborations)
  • Questions & answers

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  • cem 141 stoichiometry 1

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  • Chemistry 141
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CEM 141: Stoichiometry
the relationship between the macroscopic and microscopic worlds - ANS-Stoichiometry

is a counting term - ANS-A mole

6.022 x 10^23 things/mol - ANS-Avagrado's number

formula mass in grams - ANS-The mass of 1 mol of any substance =

mass in grams of 1 mole - ANS-Molar mass =

1) find the atomic mass of the element 2) times that by the coefficient 3) repeat with all other
elements 4) add all together - ANS-How to find molar mass

mass is conserved across the reaction - ANS-Balancing equations happens because

1) make all elements = on both sides except oxygen 2) count oxygen, if = then good 3) if not,
then double everything and recount oxygens - ANS-How to balance equation

molar mass - ANS-Mass A--> Mole A

molar ratio - ANS-Mole A --> mole B

compare and predict amount of reactants/products - ANS-Use mass/mol conversion to

molar mass and molar ratio - ANS-Mass A --> mole B

molar mass, molar ratio, molar mass - ANS-Mass A --> mass B

1. write out balanced equation
2. draw map of where you are starting and how you will get to the end
3. write out calculation w/ units
4. calculate - ANS-General procedure for converting

amount of one of the reagents which limits how much of a product can be formed - ANS-Limiting
reactant

do not compare masses directly; use moles instead, the amount of product from each reactant,
smallest = LR - ANS-To calculate LR

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