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PHYSICS CONCEPTS AND CONNECTIONS(Combined Edition)SOLUTIONS MANUAL By Igor Nowikow Brian Heimbecker
PHYSICS CONCEPTS AND CONNECTIONS(Combined Edition)SOLUTIONS MANUAL By Igor Nowikow Brian Heimbecker
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COMBINED EDITIONSolutions Manual
Igor Nowikow
Brian Heimbecker
Christopher T. Howes
Jacques Mantha
Brian P. Smith
Henri M. Van Bemmel
, Table Of Contents
I Solutions To Applying II Answers To End-
The Concepts Questions Of- Chapter
Conceptual
Chapter 1 Chapter 9 Chapter 14
Questions
Section 1.2 1 Section 9.2 18 Section 14.2 28
1.3 1 9.3 18 14.3 29 Chapter 1 37
1.4 1 9.4 18 14.5 29 Chapter 2 38
Chapter 2 9.5 19 14.6 29 Chapter 3 39
Section 2.1 1 9.6 19 14.7 29 Chapter 4 40
2.4 1 9.8 19 14.8 30 Chapter 5 43
Chapter 3 9.9 20 14.9 30 Chapter 6 45
Section 3.1 2 9.10 21 Chapter 15 Chapter 7 46
3.3 2 Chapter 10 Section 15.5 30 Chapter 8 47
3.4 3 Section 10.1 22 Chapter 16 Chapter 9 50
3.5 4 10.2 22 Section 16.4 31 Chapter 10 52
Chapter 4 10.6 22 Chapter 17 Chapter 11 55
Section 4.3 5 10.7 22 Section 17.2 32 Chapter 12 56
4.4 5 10.9 22 17.3 32 Chapter 13 57
Chapter 5 10.11 23 17.4 33 Chapter 14 61
Section 5.3 5 10.12 23 17.5 33 Chapter 15 62
5.4 5 10.13 23 17.6 33 Chapter 16 63
5.5 6 Chapter 11 17.8 34 Chapter 17 65
5.6 6 Section 11.1 23 Chapter 18 Chapter 18 66
Chapter 6 11.2 23 Section 18.2 35
Section 6.1 6 11.3 24 18.3 35
III Solutions To End-
6.2 7 11.4 24 18.4 35
Of- Chapter
6.3 8 11.5 24 18.5 35
6.4 9 Chapter 12
Problems
Chapter 1 71
6.5 10 Section 12.3 24
Chapter 2 78
Chapter 7 12.4 24
Chapter 3 90
Section 7.3 11 12.6 24
Chapter 4 106
7.4 12 12.8 24
Chapter 5 117
7.5 12 Chapter 13
Chapter 6 125
7.6 14 Section 13.4 25
Chapter 7 131
7.7 15 13.5 25
Chapter 8 141
Chapter 8 13.6 26
Chapter 9 151
Section 8.1 16 13.7 27
Chapter 10 163
8.2 16 13.8 28
Chapter 11 170
8.3 16 13.9 28
Chapter 12 178
8.4 17
Chapter 13 183
Chapter 14 192
Chapter 15 197
Chapter 16 202
Chapter 17 206
Table Of Contents Chapter 18 211
, PART 1 Solutions To Applying The Concepts
In This Section, Solutions Have Been Provided Only For Problems Requiring Calculation.
Section 1.2 i) 60 Months
4. A) C = 3.00 × 108 M/S ii) 2.6 × 106 Min
1 Second = 9 192 631 770 Vibrations iii) 1.8 × 103 D
Therefore, In 3632 S, There Are 3.34 × iv) 1.6 × 108 S
1013 Vibrations.
B) 1 M = 1 650 763.73h
Section 2.1
1. At T = 2.0 S, V = 10 M/S,
D = (.150 M)(1 M) 1
d = ——2(10 m/s + 20 m/s)2.0 s = 30 m
D = 2.48 × 105h
At T = 7.0 S, V = 15 M/S, D =12——(4.0 S)(20 M/S)
+ —21— (7.0 S — 4.0 S)(15 M/S) = 40 M + 27.5 M
Section 1.3 = 67.5 M
2. A) 4
B) 5 Section 2.4
C) 7 1. A) A = 4.0 M/S2
D) 1 T = 40.0 S
E) 4 V1 = 0 M/S
F) 6 V2 = (4.0 M/S2)(40.0 S)
3. A) 3.1 M V2 = 160 M/S
b) 3.2 M ¯→ ¯→
¯→ V 1 + V 2
c) 3.4 M B) I) Δd = —— × Δt
2
d) 3.6 M Δd = 3200 M
ii) Δ¯d→ = ¯v→1Δt + ——2¯a→Δt2
1
e) 3.4 M
4. A) 3.745 M Δd = —12— (4.0 M/S2 )(40.0 S)2
b) 309.6 M Δd = 3200 M
c) 120 S 2. A) Δd = 152 M
d) 671.6 S V1 = 66.7 M/S
e) 461.7 S V2 = 0
5. A) 4.0 M Δv = —66.7 M/S
b) 3.3 M ¯→1 + ¯→
Δd ¯→ = v—— v2
× Δt
c) 3.3333 2
d) 0.33 2Δd
Δt = ——
e) 0.333 V1 + V2
Section 1.4 Δt = 4.5577 S
¯→
¯A→ = —Δ—V
1. A) 389 S = 6.4833 Min = 0.10805 H Δt
= 4.502 × 10—3 D = 1.50 × 10—4 Months = A = —14.6 M/S2
1.25 × 10—5 A b) Δt = 4.56 S
¯V→ ¯ →
i) 1.50 × 10—4 Months c) I) Δ¯D→ = 2 +—V 1 × Δt
ii) 6.48 Min 2
iii) 1.25 × 10—8 5 A Δd =
¯→ ¯→ M 1 ¯→ 2
152
iv) 3.89 × 10 µs Ii) Δd = v1Δt + ——2Aδt
B) 5.0 A = 60 Months = 1825 D = 157 680 000 S
= 43 800 H = 2 628 000 Min
Solutions to A pp lyi ng the C onc ep t s 1
, Δd = (66.7 M/S)(4.56 S)
+ —1— (—14.6 M/S2 )(4.56 S)2 2
Δd = 152 M
2 Solutions to Applying the Concepts
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