Two-Way Frequency Table correct answers a frequency table that displays two-variable data in rows and columns
one-way frequency table correct answers table showing the number of respondents choosing each answer to a survey question
frequency polygon (line graph) correct answers raw scores on ...
QBA test 2 || with Errorless Solutions 100%.
Two-Way Frequency Table correct answers a frequency table that displays two-variable data in
rows and columns
one-way frequency table correct answers table showing the number of respondents choosing
each answer to a survey question
frequency polygon (line graph) correct answers raw scores on X-Axis, frequency on Y-Axis
discrete probability distribution correct answers consists of the values a random variable can
assume and the corresponding probabilities of the values
continuous random variable correct answers a random variable that may assume any numerical
value in an interval or collection of intervals
Binomial Probability correct answers If X has the binomial distribution with n trials and
probability p of success on each trial, the possible values of X are 0, 1, 2, ..., n.
random variable correct answers a variable whose value is a numerical outcome of a random
phenomenon
Z graph has a correct answers negative and positive side
Normal Standard Deviation correct answers .5
the range of a set of numbers is approximately equal to ________ standard deviations correct
answers 6
The units of variance are correct answers the squared units of the original numbers
Combination Formula correct answers nCr = n!/r!(n-r)!
Multiplication rule correct answers P(A ∩ B) = P(A) * P(B) is used when we are interested in the
probability of two events occurring simultaneously, or in succession.
Conditional rule correct answers P(A/B)= P(A and B)
Rules of Probability correct answers 1. The probability of any event must be between 0 and 1,
inclusive. 0 ≤ P(E) ≤ 1
2. The sum of the probabilities of all outcomes must equal 1.
3. probability of 1 means event is certain to occur and probability of 0 is certain not to occur
4. If E and F are disjoint events, then P(E or F) = P(E) + P(F). If E and F are not disjoint events,
then P(E or F) = P(E) + P(F) - P(E and F)
5. If E represents any event and Ec represents the complement of E, then P(Ec) = 1 - P(E)
6. If E and F are independent events, then P(E and F) = P(E)∗P(F)
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