100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED $9.09   Add to cart

Exam (elaborations)

PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED

 9 views  0 purchase
  • Course
  • Institution

PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED 1. Ca3N2 Ca 3 x 40.08 = 120.24 N 2 x 14.01 = 28.02 120.24 + 28.02 = 148.26 2. Li3PO4 Li 3 x 6.941 = 20.823 P 1 x 30.97 = 30.97 O 4 x 16.00 = 64.00 20.823 + 30.97 + 64.00 = 115.793 3. NH4NO3...

[Show more]

Preview 2 out of 9  pages

  • June 22, 2024
  • 9
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
avatar-seller
PORTAGE LEARNING CHEMISTRY CHEM 103 UNIT 2 EXAM
QUESTIONS WITH COMPLETE SOLUTIONS VERIFIED


1. Ca3N2
Ca 3 x 40.08 = 120.24
N 2 x 14.01 = 28.02
120.24 + 28.02 = 148.26


2. Li3PO4
Li 3 x 6.941 = 20.823
P 1 x 30.97 = 30.97
O 4 x 16.00 = 64.00
20.823 + 30.97 + 64.00 = 115.793


3. NH4NO3
N 2 x 14.01 = 28.02
H 4 x 1.008 = 4.032
O 3 x 16.00 = 48.00
28.02 + 4.032 + 48.00 = 80.052
Number your answers, and show your work. Be sure to give answers with the correct
units.
Calculate the molecular weight of the following compounds:


1. Ca3N2 ____________________


2. Li3PO4 ____________________


3. NH4NO3 ____________________
1.

, MW of NH4NO3 = 80.052
moles = 10..052 = 0.125 mole
2.
MW of Li3PO4 = 115.793
grams = 0.0500 x 115.793 = 5.79 grams
Number your answers, and show your work. Be sure to give answers with the correct
units.


Calculate the number of moles in 10.0 grams in the following compound:


1. NH4NO3 ____________________


Calculate the number of grams of each in 0.0500 mol in the following compound:


2. Li3PO4 ____________________
1. MW of Na2SO4 = 2 (22.99) + (32.07) + 4(16.00) = 142.05
%Na = 45..05 x 100 = 32.37%
%S = 32..05 x 100 = 22.58%
%O = 64..05 x 100 = 45.05%
2. MW of Ca(NO3)2 = (40.08) + 2 (14.01) + 6 (16.00) = 164.1
%Ca = 40..1 x 100 = 24.42%
%N = 28..1 x 100 = 17.07%
%O = 96..1 x 100 = 58.50%
Calculate the percent of each element present in the following compounds:
1. Na2SO4
Na = __________ S = __________ O = __________
2. Ca(NO3)2
Ca = __________ N = __________ O = __________
1.) % Composition of a compound is:
52.56% Fe 52.56% Fe ÷ 55.85 = 0.941 (smallest number of the set)
2.83% H 2.83% H ÷ 1.008 = 2.808

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller NurseAdvocate. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $9.09. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

75323 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$9.09
  • (0)
  Add to cart