100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024 $2.71   Add to cart

Exam (elaborations)

APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024

 28 views  2 purchases
  • Course
  • Institution
  • Book

APM2611 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 14 August 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... Question 1 1. Find the radius and interval of convergence of the following series: (i) ...

[Show more]

Preview 3 out of 23  pages

  • June 12, 2024
  • 23
  • 2023/2024
  • Exam (elaborations)
  • Questions & answers
avatar-seller
APM2611
ASSIGNMENT 3 2024
UNIQUE NO.
DUE DATE: 14 AUGUST 2024

, ASSIGNMENT 03
Due date: Wednesday, 14 August 2024
-

ONLY FOR YEAR MODULE

First order separable, linear, Bernoulli, exact and homogeneous equations. Higher order
homogeneous DE’s. Solving non-homogeneous DE’s using the undetermined
coefficients, variation of parameters and operator methods.

Answer all the questions. Show all your own and personalized workings, you get ZERO
to a question if we see that you have copied someone’s else solution word by word.

If you choose to submit via myUnisa, note that only PDF files will be accepted.

Note that all the questions will be marked therefore, it is highly recommended to attempt all of them.

Question 1

1. Find the radius and interval of convergence of the following series:
(i)
X∞ 100n n
(x + 7)
n=1
n!

(ii)
X∞ (−1) k k
k (x − 5)
k=1
10

2. Rewrite the expression below as a single power series:
X∞ n
X∞ X∞
n(n − 1)c n x + 2 n(n − 1)c n x n−2 + ncn x n .
n=2 n=2 n=1



Question 2

1. Verify by direct substitution that the given power series is a particular solution of the DE
00 0
X∞ (−1) n+1 n
(x + 1)y + y = 0 ; y = x .
n
n=1

2. Use the power series method to solve the initialvalue problem
00 0 0
(x + 1)y − (2 − x)y + y = 0, y(0) = 2, y (0) = −1;
where c0 and c1 are given by the initial conditions.



16

, APM2611/101/0/2024


Question 3

Calculate the Laplace transform of the following function from first principles:

1.
sin t if 0≤t<π
f (t) =
0 if t≥π

2. f (t) = e −t sin t

3. Use Theorem 7.1 to find L{f (t)}

(i) f (t) = −4t 2
+ 16t + 9
(ii) f (t) = 4t 2
− 5 sin 3t
(iii) f (t) = (e t − e −t ) 2



Question 4


1. Use Theorem 7.3 to find the inverse transform:

(i)
2s − 4
L −1
(s2 + s)(s 2 + 4)
(ii)
s
L −1
(s + 2)(s 2 + 4)
2. Use the Laplace transform to solve the initialvalue problem

y00+ 5y 0 + 4y = 0, y(0) = 1, y0(0) = 0.



Question 5

1,
1. When g(t) = 1 and L{g(t)} = G(s) = s
the convolution theorem implies that the Laplace
transform of the integral of f is
Z t
F (s)
L f (τ ) dτ = .
0
s
The inverse form is
Z t
F (s)
f (τ ) dτ = L −1 .
0
s
Find


17

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller LIBRARYpro. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $2.71. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

78075 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$2.71  2x  sold
  • (0)
  Add to cart