longer carbon chain (solubility) - correct answer less soluble
reaction rate - correct answer aA+bB --> cC+ dD
rate= -1/a(Δ[A]/Δt)= -1/b(Δ[B]/Δt)=1/c(Δ[C]/Δt)
=1/d(Δ[D]/Δt)
zero order - correct answer graph: [A] vs time
negative slope
first order - correct answer graph: ln[A] vs time
negative slope
second order - correct answer graph: 1/[A] vs time
positive slope
first order half life - correct answer each successive half life is an equal period of time
second order half life - correct answer each successive half life is twice as long as the preceding one
exothermic reaction - correct answer faster than endothermic
ΔH<0
Reverse reaction is endothermic (slower than forward)
endothermic reaction - correct answer slower than exothermic
ΔH>0
reverse reaction is exothermic (faster than forward)
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller Schoolflix. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $13.49. You're not tied to anything after your purchase.