Complete Solutions Manual for Principles of Physics, Extended, International Adaptation, 12th Edition by David Halliday, Robert Resnick, Jearl Walker ; ISBN13: 9781119820628. (Full Chapters included Chapter 1 to 44)....1. Measurement.
2. Motion Along a Straight Line.
3. Vectors.
4. Motion in Two...
Principles of Physics, 12e, International Adaptation Solutions Manual
Solutions Manual
for
Principles of Physics
Twelfth Edition
By
David Halliday, Robert Resnick, Jearl Walker
CHAPTER 1
Complete Chapter Solutions Manual
are included (Ch 1 to 44)
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,Principles of Physics, 12e, International Adaptation Solutions Manual
1. From Fig. 1.1, we see that 212 S is equivalent to 258 W and 212 – 32 = 180 S is
equivalent to 216 – 60 = 156 Z. The information allows us to convert S to W or Z.
(a) In units of W, we have
258 W
75.0 S = ( 75.0 S) = 91.27 W
212 S
(b) In units of Z, we have
156 Z
75.0 S = ( 75.0 S) = 65.0 Z
180 S
2. THINK In this problem we’re given the radius of Earth, and asked to compute its
circumference, surface area and volume.
EXPRESS Assuming Earth to be a sphere of radius
RE = ( 6.37 106 m )(10−3 km m ) = 6.37 103 km,
the corresponding circumference, surface area and volume are:
4 3
C = 2 RE , A = 4 RE2 , V= RE .
3
The geometric formulas are given in Appendix E.
ANALYZE (a) Using the formulas given above, we find the circumference to be
C = 2 RE = 2 (6.37 103 km) = 4.00 104 km.
(b) Similarly, the surface area of Earth is
( )
2
A = 4 RE2 = 4 6.37 103 km = 5.10 108 km2 ,
, Principles of Physics, 12e, International Adaptation Solutions Manual
LEARN From the formulas given, we see that C RE , A RE2 , and V RE3 . The ratios of
volume to surface area, and surface area to circumference are V / A = RE / 3 and
A / C = 2RE .
3. The metric prefixes (micro (), pico, nano, …) are given in Table 1.1.2.
100 y 365 day 24 h 60 min
(
(a) 1 century = 10−6 century ) = 52.6 min.
1 century 1 y 1 day 1 h
(b) The percent difference is therefore
52.6 min − 50 min
= 4.9%.
52.6 min
4. THINK This problem deals with conversion of furlongs to rods and chains, all of which
are units for distance.
EXPRESS Given that 1 furlong = 201.168 m, 1 rod = 5.0292 m and 1 chain = 20.117 m ,
the relevant conversion factors are
1 rod
1.0 furlong = 201.168 m = (201.168 m ) = 40 rods,
5.0292 m
and
1 chain
1.0 furlong = 201.168 m = (201.168 m ) =10 chains .
20.117 m
Note the cancellation of m (meters), the unwanted unit.
ANALYZE Using the above conversion factors, we find
40 rods
(a) the distance d in rods to be d = 3.0 furlongs = ( 3.0 furlongs ) = 120 rods,
1 furlong
10 chains
(b) and in chains to be d = 3.0 furlongs = ( 3.0 furlongs ) = 30 chains.
1 furlong
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