100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Grade 11 Mathematics (MATH) November Paper 2 and memo - 2023 (2) $2.86   Add to cart

Exam (elaborations)

Grade 11 Mathematics (MATH) November Paper 2 and memo - 2023 (2)

 20 views  0 purchase
  • Course
  • Institution

Grade 11 Math November Paper 2 and Memo: Total: 150 Marks. This exam covers the following work: Statistics | Euclidean and Analytical Geometry | Trigonometry This is a practice paper with memorandum meant to test the student's knowledge, and will not be the same paper written for the exam...

[Show more]

Preview 3 out of 17  pages

  • November 16, 2023
  • 17
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers
  • 200
avatar-seller
GRADE 11 MATHEMATICS
NOVEMBER EXAMINATION PAPER 1


QUESTION 1
1.1 Solve for x :
1.1.1 x 2−5 x−6=0 (2)

1.1.2 ( 2 x−3 ) ( x+1 ) =9 (3)

1.1.3 x−√ x−1=3 (4)

1.1.4 x ( x +10 ) >−25 (4)
2
1.1.5 x 3 =4 (3)

1.1.6 22 x −4 x−1=12 (4)

1.2 Simultaneously solve x and y :
2 x− y=1 and 3 x 2−4 xy + y 2=0 (5)

1.3 Solve the following inequalities:
1.3.1 x 2+ 5 x−6>0 (3)
1.3.2 −3 ( x+ 1 )( x−2 )< 0 (3)
[31]


QUESTION 2

2.1 x=−3 ± 2 √2 are the roots of a quadratic function, f (x), of which the y-intercept is 4.
Determine f ( x). (5)
2
x −2 x +2
2.2 Given: g( x )=
3−x
2.2.1 For which values of x will g(x ) be undefined. (2)

2.2.2 Explain why g( x ) will never equal zero. (Show all your calculations). (3)

2−x
2.3 Solve x if : < 0. Graphically represent your answer. (5)
x+5
1|Page www.summariessa.co.za M a t h e m a ti c s
Grade 11 November Paper 1

,2.4 Simplify and leave an answer with positive exponents only:



x x+1
4 3 .9
(4)
27 x+2

2.5 Without solving the equation, determine the nature of the roots of: 4 x2 =2 x +1. (5)
[24]

QUESTION 3
3.1 The first three terms of a linear series, is given as: 3 x−2 ; x+ 9; 2 x +5
3.1.1 Determine the value of x . (3)
3.1.2 Determine the numerical value of T3. (2)

3.2 Given the quadratic series: −128 ;−84 ;−48 ;−20 ; ...
3.2.1 Determine the next two terms of the series. (2)
3.2.1 Determine T n, the general term of the pattern. (3)
3.2.3 Given that T n=−4 n2 +56 n−180 , determine the largest possible
numerical value for T n . (4)

3.3 Given T n=13−3 n :
3.3.1 Which term in the series would be equal to -179. (3)
3.3.2 Determine the numerical value for the 11th term. (2)
3.4 James and John look at the following patterns:

Pattern 1 Pattern 2 Pattern 3




James says if he increases the pattern number by one, square that number and then
subtract the pattern number increased by one he will get the general formula.

John says he can derive the general formula for the number of blocks by taking the number
of columns in each pattern and multiplying if by the number of rows.

Who is correct between James and John? Prove your answer. (5)
[24]

QUESTION 4
−3
Given: f ( x)= −1 and g( x )=−a x . The point (1 ;−3) lies on g .
x +3
4.1 Determine the value of a . (2)
4.2 Draw a neat sketch of the two graphs on the same axis. Show all intercepts
with the axes and asymptote clearly. (5)
4.3 Determine the axis of simmetry of f that has a positive gradient. (2)

2|Page www.summariessa.co.za M a t h e m a ti c s
Grade 11 November Paper 1

, [9]
QUESTION 5
R(−1 ; 9) is the turning point of : f ( x )=a x2 +bx +c . P and Q are the x -intercepts of f .
TV is a straight line parallel to the y -axis. For g ( x )=x+ 4 , the x -intercept is at point P.
S is one of the intercept points between f and g .




5.1 Calculate the coordinates of P. (2)
5.2 Show that for f ,a=−1 , b=−2∧c=8. Show all your calculations. (5)
5.3 Calculate the coordinates of S, the intercept point of the two graphs f and g. (4)
5.4 Determine the maximum length of TV between the points P and S. (5)
[16]

QUESTION 6
4 1
In the figure below, where f ( x )= +3 and g ( x )= x+5 .
x +2 2




Determine the following:


3|Page www.summariessa.co.za M a t h e m a ti c s
Grade 11 November Paper 1

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller SummariesSA. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $2.86. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

75759 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$2.86
  • (0)
  Add to cart