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Straighterline chem 101 exam 4 with questions and answers

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A solution of chloroform, CHCl3, and acetone, (CH3)2CO, exhibits a negative deviation from Raoult's law. This result implies that Select one: a. chloroform-chloroform interactions are stronger than chloroform-acetone interactions. b. chloroform-chloroform interactions are weaker than chloroform...

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  • July 30, 2023
  • 11
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers
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A solution of chloroform, CHCl3, and acetone, (CH3)2CO, exhibits a negative deviation from
Raoult's law. This result implies that
Select one:
a. chloroform-chloroform interactions are stronger than chloroform-acetone interactions.
b. chloroform-chloroform interactions are weaker than chloroform-acetone interactions.
c. acetone-acetone interactions are stronger than chloroform-acetone interactions.
d. acetone-acetone interactions are weaker than chloroform-acetone interactions.
e. Choice 2 and 4


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The correct answer is: Choice 2 and 4
Question 2
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Question text
What states that the solubility of a gas in a liquid is proportional to the pressure of the gas over the solution?
Select one:
a. Entropy
b. Henry's law


c. Dissolution
d. Vapor pressure
e. Enthalpy of salvation
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The correct answer is: Henry's law
Question 3
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Question text
At 10°C one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. What
is the Henry's law constant of Cl2 in water?
(R = 0.0821 atm • L • mol–1• K–1 )
Select one:
a. 3.8 mol • L–1• atm–1
b. 0.043 mol • L–1• atm–1
c. 36 mol • L–1• atm–1
d. 3.1 mol • L–1• atm–1

, e. 0.13 mol • L–1• atm–1


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The correct answer is: 0.13 mol • L–1• atm–1
Question 4
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Safrole was once used as a flavoring in root beer, until it was banned in 1960. What
is the vapor pressure of a solution prepared by dissolving 0.75 mol of nonvolatile
safrole in 950 g of ethanol (46.07 g/mol)? P°ethanol = 50.0 torr at 25°C.
Select one:
a. 1.8 torr
b. 11 torr
c. 15 torr


d. 40 torr
e. 48 torr
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The correct answer is: 48 torr
Question 5
Correct
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Question text
What is the vapor pressure above a solution prepared by dissolving 0.500 mol of a nonvolatile
solute in 275 g of hexane (86.18 g/mol) at 49.6°C? P°hexane = 400.0 torr at 49.6°C.
Select one:
a. 54 torr
b. 154 torr
c. 246 torr
d. 346 torr


e. 400. torr
Feedback
The correct answer is: 346 torr
Question 6
Correct

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