© 2018 Pearson Education, Inc., 330 Hudson Street, NY, NY 10013. All rights reserved. This material is protected under all copyright laws as they
currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
1–1. The floor of a heavy storage warehouse building is made
of 6-in.-thick stone concrete. If the floor is a slab having a
length of 15 ft and width of 10 ft, determine the resultant force
caused by the dead load and the live load.
SOLUTION
From Table 1–3,
DL = [12 lb>ft2 # in.(6 in.)](15 ft)(10 ft) = 10,800 lb
From Table 1–4,
LL = (250 lb>ft2)(15 ft)(10 ft) = 37, 500 lb
Total load:
F = 48,300 lb = 48.3 k Ans.
Ans.
F = 48.3 k
1
,© 2018 Pearson Education, Inc., 330 Hudson Street, NY, NY 10013. All rights reserved. This material is protected under all copyright laws as they
currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
1–2. The wall is 15 ft high and consists of 2 * 4 in. studs,
plastered on one side. On the other side there is 4-in. clay brick.
Determine the average load in lb>ft of length of wall that the
wall exerts on the floor.
SOLUTION
Using the data tabulated in Table 1–3,
4@in. clay brick: (39 lb>ft2)(15 ft) = 585 lb>ft
2 * 4@in. studs plastered
on one side: (12 lb>ft2) (15 ft) = 180 lb>ft
wD = 765 lb>ft Ans.
Ans.
wD = 765 lb>ft
2
,© 2018 Pearson Education, Inc., 330 Hudson Street, NY, NY 10013. All rights reserved. This material is protected under all copyright laws as they
currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
1–3. A building wall consists of 12-in. clay brick and 12 -in.
fiberboard on one side. If the wall is 10 ft high, determine the
load in pounds per foot that it exerts on the floor.
SOLUTION
From Table 1–3,
12@in. clay brick: (115 lb>ft2)(10 ft) = 1150 lb>ft
1>2@in. fiberboard: (0.75 lb>ft2)(10 ft) = 7.5 lb>ft
Total: 1157.5 lb>ft = 1.16 k>ft Ans.
Ans.
w = 1.16k>ft
3
, © 2018 Pearson Education, Inc., 330 Hudson Street, NY, NY 10013. All rights reserved. This material is protected under all copyright laws as they
currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher.
*1–4. The “New Jersey” barrier is commonly used during
highway construction. Determine its weight per foot of length
if it is made from plain stone concrete. 4 in.
758
12 in. 558
6 in.
24 in.
SOLUTION
Cross@sectional area = 6(24) + a b(24 + 7.1950)(12) + a b(4 + 7.1950)(5.9620)
1 1
2 2
= 364.54 in2
Use Table 1–2.
l ft2
w = 144 lb>ft3(364.54 in2) a b = 365 lb>ft Ans.
144 in2
Ans.
w = 365 lb>ft
4
