∫
𝑠𝑖𝑛ℎ𝑥
𝑑𝑥
Hint:
1 + 𝑐𝑜𝑠ℎ𝑥
Que 1.3. The derivative of 1+
From
𝑐𝑜𝑠ℎ𝑥 is 𝑠𝑖𝑛ℎ𝑥
𝑓′(𝑥) Since now we know that the
∫ = 𝑙𝑛 | 𝑓(𝑥) | + 𝑐 question consist of the function and
𝑓(𝑥)
its derivative, therefore one of the
Since the derivative of 1 + cosh 𝑥 = sinh 𝑥 standard formulae has to be used
i.e.
=∫ 𝑠𝑖𝑛ℎ𝑥 𝑑𝑥 𝑙𝑛= |1 + cos ℎ 𝑥 | + 𝑐 ANS.
1+𝑐𝑜𝑠ℎ𝑥
1.4
𝜋
4 Que 1.4 To be able to integrate this
∫ 𝑠𝑖𝑛 3 𝑥. 𝑐𝑜𝑠 3 𝑥 𝑑𝑥 question easily the function has to
0
𝜋
be simplified first. Usually with this
type of questions we have to
∫04 𝑠𝑖𝑛 3 𝑥( ( 𝑐𝑜𝑠 2 𝑥 )( 𝑐𝑜𝑠𝑥 ) )𝑑𝑥 From { 𝑐𝑜𝑠 2 𝑥 = 1 − 𝑠𝑖𝑛 2 𝑥} simplify the function and leave it in
𝜋
the form
= ∫04 𝑠𝑖𝑛 3 𝑥((1 − 𝑠𝑖𝑛 2 x)(cosx))dx
𝜋
= ∫04 𝑠𝑖𝑛 3 𝑥𝑐𝑜𝑠𝑥 − 𝑠𝑖𝑛 5 𝑥 𝑐𝑜𝑠 𝑥 𝑑𝑥 In this form it can easily be solved
𝜋 𝜋 using the standard equations.
𝑠𝑖𝑛 4 𝑥 𝑠𝑖𝑛 6 𝑥
4 4
=[ ]0 −[ ]
4 6 0
𝜋
4 𝜋 𝑠𝑖𝑛 6 ( )
4
= [𝑠𝑖𝑛 ( )− ]
4 6
1
=
24
=0.042 ANS.
1.5
𝑑𝑥
∫
𝑥2 + 4𝑥 + 20
, By completing the square on the denominator.
3|Page MAT2691 OCT/NOV2010
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