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Summary Vector Algebra - Mathematics

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Summary of Vector Algebra - Mathematics accompanied by examples of questions with short answers, long answers and exercises.

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  • May 28, 2023
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Chapter 10
VECTOR ALGEBRA
10.1 Overview
10.1.1 A quantity that has magnitude as well as direction is called a vector.


 a
10.1.2 The unit vector in the direction of a is given by | a | and is represented by a .


10.1.3 Position vector of a point P (x, y, z) is given as OP = xiˆ + y ˆj+ z kˆ and its

magnitude as | OP | = x 2 + y 2 + z 2 , where O is the origin.

10.1.4 The scalar components of a vector are its direction ratios, and represent its
projections along the respective axes.

10.1.5 The magnitude r, direction ratios (a, b, c) and direction cosines (l, m, n) of any
vector are related as:

a b c
l = , m = , n= .
r r r

10.1.6 The sum of the vectors representing the three sides of a triangle taken in order is 0

10.1.7 The triangle law of vector addition states that “If two vectors are represented
by two sides of a triangle taken in order, then their sum or resultant is given by the third
side taken in opposite order”.

10.1.8 Scalar multiplication
  
If a is a given vector and λ a scalar, then λ a is a vector whose magnitude is |λ a | = |λ|
   
| a |. The direction of λ a is same as that of a if λ is positive and, opposite to that of a if
λ is negative.

, VECTOR ALGEBRA 205



10.1.9 Vector joining two points

If P1 (x1, y1,z1) and P2 (x2, y2,z2) are any two points, then

P1P2 = ( x2 − x1 ) iˆ + ( y2 − y1 ) ˆj + ( z2 − z1 ) kˆ


| P1P2 | = ( x2 − x1 ) 2 + ( y2 − y1 ) 2 + ( z2 − z1 ) 2

10.1.10 Section formula

The position vector of a point R dividing the line segment joining the points P and Q

whose position vectors are a and b

 
na + mb
(i) in the ratio m : n internally, is given by
m+n

 
mb – na
(ii) in the ratio m : n externally, is given by
m–n

 
  a. b  
10.1.11 Projection of a along b is  and the Projection vector of a along b
|b|

 a . b 
is   b .
 |b | 

10.1.12 Scalar or dot product
 
The scalar or dot product of two given vectors a and b having an angle θ between
them is defined as
   
a . b = | a | | b | cos θ

10.1.13 Vector or cross product
 
The cross product of two vectors a and b having angle θ between them is given as
   
a × b = | a | | b | sin θ n̂ ,

, 206 MATHEMATICS


   
where n̂ is a unit vector perpendicular to the plane containing a and b and a , b , n̂
form a right handed system.
 
10.1.14 If a = a1 iˆ + a2 ˆj + a3 kˆ and b = b1 iˆ + b2 ˆj + b3 kˆ are two vectors and λ is
any scalar, then
 
a + b = (a1 + b1 ) iˆ + (a2 + b2 ) ˆj + (a3 + b3 ) kˆ


λ a = (λ a1 ) iˆ + (λ a2 ) ˆj + (λ a3 ) kˆ

 
a . b = a1 b1+ a2 b2 + a3 b3


iˆ ˆj kˆ
  a b1 c1
a ×b = 1 = (b1c2 – b2c1) iˆ + (a2c1 – c1c2) ĵ + (a1bb – a2b1) k̂
a2 b2 c2

 
Angle between two vectors a and b is given by

  a1 b1 + a2 b2 + a3b3
a. b
cos θ = |  | |  | = 2
a b a1 + a22 + a32 b12 + b22 + b32

10.2 Solved Examples
Short Answer (S.A.)
Example 1 Find the unit vector in the direction of the sum of the vectors
 
a = 2 iˆ − ˆj + 2 kˆ and b = – iˆ + ˆj + 3 kˆ .

  
Solution Let c denote the sum of a and b . We have


c = (2 iˆ − ˆj + 2 kˆ) + (−iˆ + ˆj + 3 kˆ) = iˆ + 5 kˆ


Now | c | = 12 + 52 = 26 .

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