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Summary Differential Equations

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Calculus is a branch of mathematics that deals with the study of rates of change and slopes of curves. It is divided into two main branches: Differential Calculus and Integral Calculus. Differential Calculus: Limits: In differential calculus, limits are used to determine the behavior of a fun...

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  • February 9, 2023
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Differential Calculus


Limits
Let's consider the function f(x) = 1/x. As x approaches 0, the value of the function approaches
infinity. This can be seen by calculating the limit of the function as x approaches 0, which would be
represented as lim x→0 f(x) = ∞. This means that as x gets arbitrarily close to 0, the value of the
function becomes arbitrarily large.

Examples
One way to solve limits in differential calculus is to use algebraic methods. Let's consider the limit of
the function f(x) = x^2 - 4x + 4 as x approaches 2. To find the limit, we need to find the value that f(x)
approaches as x approaches 2.

One method is to simply substitute x = 2 into the function and see what value we get:

f(2) = 2^2 - 4 * 2 + 4 = 0

So, f(x) approaches 4 as x approaches 2. We can also write this as:

lim x→2 (x^2 - 4x + 4) = 0

This means that as x gets arbitrarily close to 2, the value of f(x) gets arbitrarily close to 0. In other
words, the limit of f(x) as x approaches 2 is 0.

Another method is to use algebraic manipulations to simplify the function and then substitute x = 2
into the simplified expression. For example, we could factor the function f(x) as:

f(x) = (x - 2)^2

Then, when we substitute x = 2 into the function, we get:

f(2) = (2 - 2)^2 = 0^2 = 0

So, the limit of f(x) as x approaches 2 is 0.

These methods illustrate how to solve limits in differential calculus using algebraic techniques. By
finding the value that a function approaches as x approaches a certain value, we can understand the
behavior of the function near that value.



Derivatives

Let's consider the function f(x) = x^2. The derivative of this function would be represented as f'(x) =
2x. The derivative represents the rate of change of the function at a given point. For example, if x =
2, the derivative f'(x) = 4, which means that the rate of change of the function at x = 2 is 4.

Differentiation rules: The power rule states that the derivative of x^n, where n is a constant, is
nx^(n-1). So, if we consider the function f(x) = x^2, the derivative would be 2x. The product rule
states that the derivative of the product of two functions is the derivative of the first function times

, the second function plus the first function times the derivative of the second function. The quotient
rule states that the derivative of the quotient of two functions is given by the derivative of the
numerator divided by the denominator minus the numerator times the derivative of the
denominator divided by the denominator squared. The chain rule states that if a function g is
composed with another function f, then the derivative of the composite function is the derivative of
the outer function evaluated at the inner function times the derivative of the inner function.

Examples


For example, let's consider the function f(x) = x^3. To find the derivative using the power rule, we
would multiply the exponent (3) by x and decrease the exponent by 1:

f'(x) = 3x^(3-1) = 3x^2

So, the derivative of x^3 is 3x^2.

Let's consider another example: the product rule, which states that the derivative of the product of
two functions, f(x) and g(x), is given by:

(f(x)g(x))' = f'(x)g(x) + f(x)g'(x)

For example, let's consider the function h(x) = x^2 * sin(x). To find the derivative using the product
rule, we would first find the derivatives of x^2 and sin(x), which are 2x and cos(x) respectively. Then,
we would multiply each derivative by the corresponding function and add the results:

h'(x) = 2x * sin(x) + x^2 * cos(x)

So, the derivative of x^2 * sin(x) is 2x * sin(x) + x^2 * cos(x).

These examples illustrate how to use differentiation rules to differentiate functions in differential
calculus. By using rules like the power rule and the product rule, we can find the derivative of a wide
variety of functions, and use the derivative to understand the behavior of the original function.



Implicit differentiation
Implicit differentiation is used when a function is not explicitly defined, but is defined implicitly by an
equation. For example, consider the equation x^2 + y^2 = 9. This equation defines a circle with a
radius of 3 centered at the origin. To differentiate this equation, we would take the derivative of
both sides with respect to x. This would give us 2x + 2yy' = 0, where y' represents the derivative of y
with respect to x. Solving for y' would give us the derivative of y implicitly defined in terms of x.

Examples
For example, consider the equation x^2 + y^2 = 9. This equation defines a circle centered at the
origin with a radius of 3. To find the derivative of y with respect to x, we would differentiate both
sides of the equation implicitly with respect to x.

Starting with the left-hand side, we would differentiate x^2 with respect to x to get 2x, and
differentiate y^2 with respect to x using the chain rule to get 2y * dy/dx. On the right-hand side, the
derivative is simply 0, since 9 is a constant.

Putting everything together, we have:

2x + 2y * dy/dx = 0

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