PHYSICS 151 Lab 10_ Natural Oscillations with a Spring-2-REVIEWED BY EXPERTS-GRADED A+
8 views 0 purchase
Course
PHYSICS 151
Institution
University Of Hawaii, Manoa
OBJECTIVE
When a spring is stretched, and elongated it has a force applied to it. This process is on
the basis that the spring is constant. This experiment we will be using a spring to confirm
whether or not there is a way to measure the constant of a spring.
THEORY
When starting from a static...
manoaphysics 151lab 10 natural oscillations with a spring 2
Written for
University of Hawaii, Manoa
PHYSICS 151
All documents for this subject (2)
Seller
Follow
Examhack
Reviews received
Content preview
OBJECTIVE
When a spring is stretched, and elongated it has a force applied to it. This process is on
the basis that the spring is constant. This experiment we will be using a spring to confirm
whether or not there is a way to measure the constant of a spring.
THEORY
When starting from a static point of view, Hooke’s law explains the stretch x of a spring
depends on the force applied F, which can be seen as the following where k is the spring constant
of s specific spring:
F = - kx
When combined with Newton’s second law of F = ma, where m is the mass attached to the
spring, and a i s the acceleration of the mass, it becomes:
ma = - kx
In this experiment acceleration a, is replaced with gravitational acceleration g giving us
x = (g / k) m
To find the spring constant, different elongations for different masses are measured. This is
described as a dynamic perspective. When the mass is attached to the spring, it will stretch and
elongate and then begin to oscillate. This results in a “simple harmonic motion.” This means that
over a certain amount of time the mass will return to the original position and velocity that it
started out with. To measure this, elongation of a spring can be shown as a function of time
where A(o) is the amplitude, and ω(o) i s the angular frequency.
x = A(o) sin( ω(o) t )
, Which is related to the period T that it takes to go through one full cycle which is
T = 1 / f = 2π / ω(o)
Velocity and acceleration of the oscillation can be calculated from the sine wave equation as a
function of time, shown as
v = ω(o) A(o) cos( ω(o) t )
and
a = -ω(o)2 A(o) sin(ω(o) t).
To achieve the relationship between the spring constant and the period, equations can be
combined to give the following:
k = ω(o)2 m = ( 4π2 / T2 ) m
This experiment works off the assumption that the mass that is attached to the spring is higher
than the mass of the spring itself.
PROCEDURE
In this experiment, different springs have different values for k. Before starting trials,
allow the spring to hang from the stand and take a measurement of the unstretched length. This is
one of the measurements needed to calculate how far the spring stretches.
FOR STATIC MEASUREMENTS
● Add weight to spring and measure how far spring is stretched
● Use masses 100 - 300 g in increments of 50 g
● Record the displacement and the corresponding mass
FOR DYNAMIC MEASUREMENTS
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller Examhack. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $11.49. You're not tied to anything after your purchase.