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Engineering and Chemical Thermodynamics 2nd Edition Solutions Manual
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  • ENG101
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  • University Of San Andrés (UdeSA )
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  • Engineering and Chemical Thermodynamics

Complete Solutions Manual of Engineering and Chemical Thermodynamics 2nd Edition by Wyatt Tenhaeff and Milo Koretsky. Solutions for all 9 chapters.

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  • March 17, 2024
  • 1641
  • 2023/2024
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  • engi
  • engineering and chemical thermodynamics solutions
  • solutions engineering and chemical thermodynamics
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Chapter 1 Solutions
Engineering and Chemical Thermodynamics




Wyatt Tenhaeff
Milo Koretsky

Department of Chemical Engineering
Oregon State University

koretsm@engr.orst.edu

,1.2
An approximate solution can be found if we combine Equations 1.4 and 1.5:

mV = ekmolecular
1 2
2
kT = ekmolecular
3
2


∴V ≈
 3kT
m

Assume the temperature is 22 ºC. The mass of a single oxygen molecule is m = 5.14 × 10 −26 kg .
Substitute and solve:

V = 487.6 [m/s]



The molecules are traveling really, fast (around the length of five football fields every second).

Comment:
We can get a better solution by using the Maxwell-Boltzmann distribution of speeds that is
sketched in Figure 1.4. Looking up the quantitative expression for this expression, we have:

 m   m 2 2
f (v)dv = 4π   exp− v v dv
3/ 2


 2πkT   2kT 

where f(v) is the fraction of molecules within dv of the speed v. We can find the average speed
by integrating the expression above


∫ f (v)vdv
∞



V = = = 449 [m/s]

πm
8kT

∫ f (v)dv
∞
0




0




2

,1.3
Derive the following expressions by combining Equations 1.4 and 1.5:

Va2 = Vb2 =
 3kT  3kT
ma mb

Therefore,

 =
Va2 mb
Vb2 ma

Since m b is larger than m a , the molecules of species A move faster on average.




3

, 1.4
We have the following two points that relate the Reamur temperature scale to the Celsius scale:

(0 º C, 0 º Reamur ) and (100 º C, 80 º Reamur )
Create an equation using the two points:

T (º Reamur ) = 0.8 T (º Celsius )

At 22 ºC,

T = 17.6 º Reamur




4

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